WPF 自定义ContextMenu且为左键点击显示
1<Button Click="Button_Click_3" Style="{StaticResource NormalButtonStyle}"> 2 <Canvas> 3 <Line X1="-5" Y1="-4" X2="5" Y2="-4" Fill="White" Stroke="White" StrokeThickness="1"/> 4 <Line X1="-5" Y1="-4" X2="-5" Y2="4" Fill="White" Stroke="White" StrokeThickness="1"/> 5 <Line X1="-5" Y1="4" X2="5" Y2="4" Fill="White" Stroke="White" StrokeThickness="1"/> 6 <Line X1="5" Y1="-4" X2="5" Y2="4" Fill="White" Stroke="White" StrokeThickness="1"/> 7 </Canvas> 8 <Button.ContextMenu> 9 <ContextMenu Name="menu" Placement="MousePoint" Width="200"> 10 <MenuItem Header="Item1"/> 11 <MenuItem Header="Item2"/> 12 <MenuItem Header="Item3"/> 13 <MenuItem Header="Item4"/> 24 </ContextMenu> 25 </Button.ContextMenu> 26</Button>
上为XAML设计代码,Style部分是Button的样式。
Canvas内的代码是Line,图案是一个方框。怎么修改可自行百度
左键显示Menu代码如下
private void Button_Click_3(object sender, RoutedEventArgs e) { //获取或设置一个值,该值指示 System.Windows.Controls.ContextMenu 是否可见。 this.menu.IsOpen = true; }
本文来自博客园,作者:_蔚蓝,转载请注明原文链接:https://www.cnblogs.com/SunsetAzure/p/4711511.html