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一、此次程序需要实现:

  1、设定固定的用户名密码

  2、用户名密码输入正确打印登录正确信息

  3、仅仅运行三次登录

二、本次使用的python版本为:

  Windows下版本号:

  C:\Users\daisy>python --version
  Python 2.7.13rc1

  Linux下版本号:

三、设计思路:

  1、定义用户名变量:USER_name = "admin1"

  2、定义密码变量:PASSWORD = "admin123"

  3、由于必须实现3次登录可以采用循环。

四、程序以windows下程序:

  以下是在pycharm下编写程序及操作使用raw_input输入:

USER_name = "admin1"        #定义用户名
PASSWORD = "admin123"     #定义密码
for i in range(3):                   #执行3次
    input_name = raw_input("input your name:")      #输入用户名
    input_pass = raw_input("input your passwd:")    #输入密码
    if input_name == USER_name and input_pass == PASSWORD:     #条件语句如果用户名密码正确中中执行以下操作不表示登录成功。
        print("you are right.")
        print("login is right.")
        break                                                                                     #登录成功跳出循环
    else:
        print("your name is wrong.")                                                   #登录用户名密码错误输出错误。
else:
    print("input too many count.")                                                     #循环完成三次登录都不成功输出。

  执行结果:

  执行三次错误用户名和密码:

  input your name:admin
  input your passwd:admin
  your name is wrong.
  input your name:admin
  input your passwd:admin
  your name is wrong.
  input your name:admin
  input your passwd:passwd
  your name is wrong.
  input too many count.

  执行正确用户名密码:

  input your name:admin
  input your passwd:admin
  your name is wrong.
  input your name:admin1
  input your passwd:admin123
  you are right.
  login is right.

  在pycharm下编写程序及操作使用input输入:

USER_name = "admin1"        #定义用户名
PASSWORD = "admin123"     #定义密码
for i in range(3):                   #执行3次
    input_name = input("input your name:")      #输入用户名
    input_pass = input("input your passwd:")    #输入密码
    if input_name == USER_name and input_pass == PASSWORD:     #条件语句如果用户名密码正确中中执行以下操作不表示登录成功。
        print("you are right.")
        print("login is right.")
        break                                                                                     #登录成功跳出循环
    else:
        print("your name is wrong.")                                                   #登录用户名密码错误输出错误。
else:
    print("input too many count.")                                                     #循环完成三次登录都不成功输出。 

  测试报错:

  input your name:admin
  Traceback (most recent call last):
    File "C:/Users/daisy/PycharmProjects/s12/day1/login��.py", line 6, in <module>
      input_name = input("input your name:")
    File "<string>", line 1, in <module>
  NameError: name 'admin' is not defined

  Process finished with exit code 1

  原因input与raw_input区别:

  >>> input_name = input("input your name:")
  input your name:23
  >>> type(input_name)
    input your name:23
  >>> type(input_name)
  <type 'str'>                                           #表示字符串

  由此可见:input默认输出为整型,raw_input默认输出为字符串:

  使用input解决方法:(将输入的值用引号引起来表示是字符串 )

  input your name:"admin"
  input your passwd:"admin123"      
  your name is wrong.
  input your name:"admin1"
  input your passwd:"admin123"
  you are right.
  login is right.

  总结:由此可见2.X版本最好使用raw_input输入字符串,那么raw_input如何输入数字类型呢?

  以下是方法:

  >>> input_name = int(raw_input("input your name:"))    #采用int表示整型:
  input your name:23
  >>> type(input_name)
  <type 'int'>                                                                 #确实是int类型:

  >>> input_name = float(raw_input("input your name:"))  #采用浮点:
  input your name:23
  >>> type(input_name)
  <type 'float'>                                                                #确实是浮点类型:
  >>>

四、程序以在Linux下程序:  

  [root@localhost ~]# python3 --version    
  Python 3.5.2                                                                 #版本:                  
  [root@localhost ~]# python3
  Python 3.5.2 (default, Apr  9 2017, 00:21:30)
  [GCC 4.4.7 20120313 (Red Hat 4.4.7-18)] on linux
  Type "help", "copyright", "credits" or "license" for more information.
  >>>

  >>> USER_name = "admin1"

  PASSWORD = "admin123"
  # input_num = 1
  >>> >>> ... # input_count = 0
  ... for i in range(1, 4):
  ...     input_name = input("input your name:")
  ...     input_pass = input("input your passwd:")
  ...     if input_name == USER_name and input_pass == PASSWORD:
  ...         print("you are right.")
  ...         print("login is right.")
  ...         break
  ...     else:
  ...         print("your name is wrong.")
  ... else:
  ...     print("input too many count.")
  ...
  input your name:admin
  input your passwd:admin
  your name is wrong.
  input your name:admin1
  input your passwd:admin123
  you are right.
  login is right.
  >>>

  由于3.x版本已经精简所以使用input不会报错也不需要将输入的值用引号引起来表示字符。

  那么我们测试以下input输入的类型:

  先输入数字:

  >>> input_name = input("input your name:")
  input your name:23

  >>> type(input_name)          
  <class 'str'>                                                       #也是字符串

  同样的想在3.X中输入数字类型可以采用int、float等。可参考上文。

posted on 2017-04-11 13:44  Steward_Xu  阅读(1085)  评论(0编辑  收藏  举报