阿里钉钉面试题

定义一个类对list进行封装,使得可以用下标对list进行操作:
 1 #include <list>
#include <vector>
#include <iostream>
#include <string> 

using namespace std;

class Test
{
public:
    Test();
    //~Test();
    Test(list<string> strList);
    string &operator[](int n); //一般这里需要有&的,可以防止对象返回时去调用构造函数(因为return值,会有一个把值拷贝下来的过程)

public:
    list<string> m_strList;
};


Test::Test(list<string> strList)
{
    m_strList = strList;
}

//Test::~Test()    //当定义析构函数,而没有实现时会报错.
//{
//
//}

string& Test::operator[](int n)
{
    list<string>::iterator i = m_strList.begin();
    vector<list<string>::iterator> vecStrIter;
    for (; i != m_strList.end(); i++)
    {
        vecStrIter.push_back(i);
    }
    return *(vecStrIter[n]);
}


int main()
{
    string str[4] = {"a", "li", "ba", "ba!"};
    list<string> strList(str, str+4);
    Test test(strList);
    cout << test[1] << endl;
    return 0;
}