分布式数据库技术.作业1-3
作业1
针对world数据库、进行如下查询:
1. 查询Asia的所有国家名,国家代码,城市名
SELECT country.`Name` AS CountryName,country.`Code`,city.`Name` as CityName
FROM COUNTRY,city
WHERE country.`Code`=city.CountryCode AND country.Continent='Asia';
2.查询Asia中每个国家的城市数量,按查询结果降序排列
SELECT country.`Name` AS CountryName,country.`Code`,COUNT(city.`Name`) AS CityNum
FROM COUNTRY,city
WHERE country.`Code`=city.CountryCode AND country.Continent='Asia'
GROUP BY `Code`
ORDER BY CityNum DESC;
3. 查询CHN中每个District的人口总数,按降序排列
SELECT District,SUM(Population) AS DistrictPopulationSum
FROM CITY
WHERE CountryCode="CHN"
GROUP BY District
ORDER BY DistrictPopulationSum DESC;
作业2
针对 world 数据库、进行如下查询:
USE world;
1、查询每个 Continent 中 GNP 最高和最低的国家信息及其对应的 GNP 的值
SELECT country.*
FROM country
RIGHT JOIN
(SELECT Continent,
MAX(GNP) AS GNP_MAX
FROM country
WHERE GNP!=0
AND Population!=0
GROUP BY Continent) AS assist ON country.GNP=assist.GNP_MAX
AND country.Continent=assist.Continent
ORDER BY GNP DESC;
SELECT country.*
FROM country
RIGHT JOIN
(SELECT Continent,
MIN(GNP) AS GNP_MIN
FROM country
WHERE GNP!=0
AND Population!=0
GROUP BY Continent) AS assist ON country.GNP=assist.GNP_MIN
AND country.Continent=assist.Continent
ORDER BY GNP DESC;
2、查询每个 Continent 中人均 GNP 最高和最低的国家信息及其对应的人均 GNP 的值
SELECT country.*
FROM
(SELECT GNP/Population AS PerCapitaGNP,
country.*
FROM country) AS country
RIGHT JOIN
(SELECT Continent,
MAX(GNP/Population) AS PerCapitaGNP
FROM country
WHERE GNP!=0
AND Population!=0
GROUP BY Continent) AS assist ON country.PerCapitaGNP=assist.PerCapitaGNP
AND country.Continent=assist.Continent
ORDER BY PerCapitaGNP DESC;
SELECT country.*
FROM
(SELECT GNP/Population AS PerCapitaGNP,
country.*
FROM country) AS country
RIGHT JOIN
(SELECT Continent,
MIN(GNP/Population) AS PerCapitaGNP
FROM country
WHERE GNP!=0
AND Population!=0
GROUP BY Continent) AS assist ON country.PerCapitaGNP=assist.PerCapitaGNP
AND country.Continent=assist.Continent
ORDER BY PerCapitaGNP DESC;
3、查询每个 Continent 中总面积(SurfaceArea)最高和最低的国家及其对应的 SurfaceArea 的值
SELECT country.*
FROM country
RIGHT JOIN
(SELECT Continent,
MAX(SurfaceArea) AS SurfaceArea_MAX
FROM country
WHERE GNP!=0
AND Population!=0
GROUP BY Continent) AS assist ON country.SurfaceArea=assist.SurfaceArea_MAX
AND country.Continent=assist.Continent
ORDER BY SurfaceArea DESC;
SELECT country.*
FROM country
RIGHT JOIN
(SELECT Continent,
MIN(SurfaceArea) AS SurfaceArea_MIN
FROM country
WHERE GNP!=0
AND Population!=0
GROUP BY Continent) AS assist ON country.SurfaceArea=assist.SurfaceArea_MIN
AND country.Continent=assist.Continent
ORDER BY SurfaceArea DESC;
4、查询每个 Continent 中人均面积(SurfaceArea)最高和最低的国家及其对应的人均 SurfaceArea 的值
SELECT country.*
FROM
(SELECT SurfaceArea/Population AS PerCapitaSurfaceArea,
country.*
FROM country) AS country
RIGHT JOIN
(SELECT Continent,
MAX(SurfaceArea/Population) AS PerCapitaSurfaceArea
FROM country
WHERE GNP!=0
AND Population!=0
GROUP BY Continent) AS assist ON country.PerCapitaSurfaceArea=assist.PerCapitaSurfaceArea
AND country.Continent=assist.Continent
ORDER BY PerCapitaSurfaceArea DESC;
SELECT country.*
FROM
(SELECT SurfaceArea/Population AS PerCapitaSurfaceArea,
country.*
FROM country) AS country
RIGHT JOIN
(SELECT Continent,
MIN(SurfaceArea/Population) AS PerCapitaSurfaceArea
FROM country
WHERE GNP!=0
AND Population!=0
GROUP BY Continent) AS assist ON country.PerCapitaSurfaceArea=assist.PerCapitaSurfaceArea
AND country.Continent=assist.Continent
ORDER BY PerCapitaSurfaceArea DESC;
*注意:population 为 0 不记录
作业3
1、将关系Country分成了两个子关系,Region=‘Middle East’和Region=‘Southern and Central Asia’
分片条件 C1: Region='Middle East'
C2: Region=‘Southern and Central Asia’
证明:和是Country水平分片
欲证明,和是Country水平分片,须证明如下三点:
C_1,C_2 和Country关系模式相同;
C_1∪C_2=Country
C_1∩C_2=Ф
2. 有Country关系如下
Country { code , Name , Continent , Region , population ,GNP }
假设 C1{ code , Name , Continent , Region }
C2{code , population ,GNP}
证明:C1和C2是Country垂直分片
根据垂直分片条件,可知:
C_1和C_2是Country的无损分解。
Attr(C_1 )∪Attr(C_2 )=Attr(Country)
Attr(C_1 )∩Attr(C_2 )={Code}
因此,C_1和C_2是Country的垂直分片
本文来自博客园,作者:海边星,转载请注明原文链接:https://www.cnblogs.com/StarsbySea/p/15575151.html