摘要: select Student.S_ID, Student.Sname, count(SC.C_ID), sum(score) from Student left Outer join SC on Student.S_ID=SC.S_ID group by Student.S_ID,Sname 阅读全文
posted @ 2020-11-24 14:43 抬头就能看到阳光 阅读(6510) 评论(0) 推荐(0) 编辑
摘要: select S_ID,avg(score) from sc group by S_ID having avg(score) >60; 阅读全文
posted @ 2020-11-24 14:42 抬头就能看到阳光 阅读(885) 评论(0) 推荐(0) 编辑
摘要: select a.s_id from (select s_id,score from SC where C_ID='001') a,(select s_id,scorefrom SC where C_ID='002') b where a.score>b.score and a.s_id=b.s_i 阅读全文
posted @ 2020-11-24 14:41 抬头就能看到阳光 阅读(699) 评论(0) 推荐(0) 编辑