摘要: def SlowSnail(score): name = input('请输入姓名:') if score >= 90: grade = 'A' elif score >= 60: grade = 'B' else: grade = 'C' print('%s的成绩是%d,属于等级%s' % (na 阅读全文
posted @ 2022-08-29 15:55 放氮气的蜗牛 阅读(129) 评论(0) 推荐(0) 编辑