摘要: #include<stdio.h> void main() { int n, i, j; for (n = 1000; n < 10000; n++) { i = n / 100; j = n % 100; if (n == ((i + j) * (i + j))) printf("%d\n", n 阅读全文
posted @ 2022-06-15 16:34 放氮气的蜗牛 阅读(127) 评论(0) 推荐(0) 编辑