C# WinForm 用MenuStrip动态生成菜单并动态加载事件
2011-09-27 11:13 ※森林小居※ 阅读(15891) 评论(9) 编辑 收藏 举报最近在做WINFORM开发,一直都在为主界面的点击事件及动态加载菜单苦脑。现在已解决这个问题了,可以实现数据库或都XML等配置完成动态生成菜单及事件加载。代码如下:
private void Form1_Load(object sender, EventArgs e) { //添加菜单一 ToolStripMenuItem subItem; subItem = AddContextMenu("入库", menuStrip1.Items, null); //添加子菜单 AddContextMenu("添加入库", subItem.DropDownItems, new EventHandler(MenuClicked)); AddContextMenu("入库管理", subItem.DropDownItems, new EventHandler(MenuClicked)); //添加菜单二 subItem = AddContextMenu("出库", menuStrip1.Items, null); //添加子菜单 AddContextMenu("添加出库", subItem.DropDownItems, new EventHandler(MenuClicked)); AddContextMenu("出库管理", subItem.DropDownItems, new EventHandler(MenuClicked)); } /// <summary> /// 添加子菜单 /// </summary> /// <param name="text">要显示的文字,如果为 - 则显示为分割线</param> /// <param name="cms">要添加到的子菜单集合</param> /// <param name="callback">点击时触发的事件</param> /// <returns>生成的子菜单,如果为分隔条则返回null</returns> ToolStripMenuItem AddContextMenu(string text, ToolStripItemCollection cms, EventHandler callback) { if (text == "-") { ToolStripSeparator tsp = new ToolStripSeparator(); cms.Add(tsp); return null; } else if (!string.IsNullOrEmpty(text)) { ToolStripMenuItem tsmi = new ToolStripMenuItem(text); tsmi.Tag = text + "TAG"; if (callback != null) tsmi.Click += callback; cms.Add(tsmi); return tsmi; } return null; } void MenuClicked(object sender, EventArgs e) { //以下主要是动态生成事件并打开窗体 //((sender as ToolStripMenuItem).Tag)强制转换 ObjectHandle t = Activator.CreateInstance("WinForms", "WinForms.Form2"); Form f = (Form)t.Unwrap(); f.ShowDialog(); }