摘要: SELECT customer_id, SUM(order_amount) as total_orders, MAX(order_date) as latest_order_date FROM orders WHERE order_date < DATE_SUB(NOW(), INTERVAL 30 阅读全文
posted @ 2023-12-01 08:57 丶漏电姐姐 阅读(29) 评论(0) 推荐(0) 编辑