通过key_len分析联合索引的使用
The key_len column indicates the length of the key that MySQL decided to use. The length is NULL if the key column says NULL. Note that the value of key_len enables you to determine how many parts of a multiple-part key MySQL actually uses.
数据库版本及数据表结构如下
mysql> select version(); +------------+ | version() | +------------+ | 5.6.10-log | +------------+ 1 row in set mysql> show create table usercasinoresult_11; +---------------------+-------------------------------------------------+ | Table | Create Table | +---------------------+-------------------------------------------------+ | usercasinoresult_11 | CREATE TABLE `usercasinoresult_11` ( `CasinoID` varchar(64) NOT NULL, `UserID` bigint(20) NOT NULL DEFAULT '0', `NickName` varchar(45) NOT NULL, `LastUpdateTime` datetime NOT NULL, `GameSpecified` varchar(500) DEFAULT NULL, PRIMARY KEY (`CasinoID`,`UserID`), KEY `IX_UserID_LastUpdateTime` (`UserID`,`LastUpdateTime`) ) ENGINE=InnoDB DEFAULT CHARSET=utf8mb4 | +---------------------+-------------------------------------------------+ 1 row in set
对于联合索引IX_UserID_LastUpdateTime,我们可以计算key_len的最大可能长度为13 bytes(BIGINT NOT NULL(8 bytes)+DATETIME NOT NULL(5 bytes + fractional seconds storage))
两个语句对应的Explain
mysql> explain select CasinoID, unix_timestamp(LastUpdateTime) as LastUpdateTime from usercasinoresult_11 where UserID = 108375 and unix_timestamp(LastUpdateTime) < 1500981297 and unix_timestamp(LastUpdateTime) > 1500376497 order by LastUpdateTime desc limit 30; mysql> explain select CasinoID, unix_timestamp(LastUpdateTime) as LastUpdateTime from usercasinoresult_11 where UserID = 108375 and LastUpdateTime < '2017-07-25 19:14:57' and LastUpdateTime > '2017-07-18 19:14:57' order by LastUpdateTime desc limit 30;
第1个查询的key_len=8,它仅使用的联合索引中的UserID,从语句中我们也可以看到where条件在联合索引的第2列使用的函数unix_timestamp(LastUpdateTime),得到UserID后只能Scan所有记录。
第2个查询的key_len=13,它使用了整个联合索引,得到UserID后,再使用联合索引的第2列进行范围查找。
因为不懂,所以加倍努力!