Oracle转换字符串为数组

1. CREATE OR REPLACE TYPE mytable AS TABLE OF varchar2(500);

2. 方法:

CREATE OR REPLACE FUNCTION SEND_SPLIT (src VARCHAR2, delimiter varchar2)
RETURN mytable IS
psrc
VARCHAR2(500);
a mytable :
= mytable();
i
NUMBER := 1;
j
NUMBER := 1;
BEGIN
psrc :
= RTrim(LTrim(src, delimiter), delimiter);
LOOP
i :
= InStr(psrc, delimiter, j);
--Dbms_Output.put_line(i);
IF i>0 THEN
a.extend;
a(a.
Count) := Trim(SubStr(psrc, j, i-j));
j :
= i+1;
--Dbms_Output.put_line(a(a.Count-1));
END IF;
EXIT WHEN i=0;
END LOOP;
IF j <= Length(psrc) THEN
a.extend;
a(a.
Count) := Trim(SubStr(psrc, j, Length(psrc)+1-j));
END IF;
RETURN a;
END;

3.测试:

SELECT * FROM users WHERE userid in (SELECT * FROM TABLE(CAST(SEND_SPLIT(UIDS, ',')AS mytable)))

posted on 2011-07-04 10:48  Scarface  阅读(12214)  评论(2编辑  收藏  举报

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