Spring 简单入门实例

  • 首先新建一个Web 项目
  • 导入相应Jar 包
  • <?xml version="1.0" encoding="UTF-8"?>
    <beans
    	xmlns="http://www.springframework.org/schema/beans"
    	xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
        xmlns:p="http://www.springframework.org/schema/p"
        xmlns:context="http://www.springframework.org/schema/context"
        xmlns:mvc="http://www.springframework.org/schema/mvc"
        xsi:schemaLocation="
            http://www.springframework.org/schema/beans
            http://www.springframework.org/schema/beans/spring-beans.xsd
    		http://www.springframework.org/schema/mvc
            http://www.springframework.org/schema/mvc/spring-mvc.xsd
            http://www.springframework.org/schema/context
            http://www.springframework.org/schema/context/spring-context.xsd">
      <bean id="say" class="com.hh.spring.SpringTest">
      		<property name="name" value="张嘎"></property>
      		<property name="content" value="三天不打小鬼子,手都痒痒!"></property>
      </bean>
            
    	
    </beans>
    

      

  • package com.hh.spring;
    
    import org.springframework.context.ApplicationContext;
    import org.springframework.context.support.ClassPathXmlApplicationContext;
    
    public class SpringTest {
    
    	private String name;
    	
    	private String content;
    	
    	public String getName() {
    		return name;
    	}
    
    	public void setName(String name) {
    		this.name = name;
    	}
    
    	public String getContent() {
    		return content;
    	}
    
    	public void setContent(String content) {
    		this.content = content;
    	}
    
    	private void say(){
    		System.out.println(name+"说:"+content);
    	}
    	
    	public static void main(String[] args) {
    		ApplicationContext ctx = new ClassPathXmlApplicationContext("applicationContext.xml");
    		SpringTest zhangGa = ctx.getBean("say",SpringTest.class);
    		zhangGa.say();
    	}
    }
    

      

posted @ 2017-01-09 09:32  八十年代的金坛县  阅读(188)  评论(0编辑  收藏  举报