F(n) = F(n-1)+ F(n-2) + F(n-3)+ F(N-4) (N>=5)F(1) = 1;F(2) = F(1)+1 = 2;F(3) = F(2) + F(1) + 1 = 4;F(4) =F(3) + F(2) + F(1) +1 = 8;
posted on 2010-09-14 18:21 SammyLan 阅读(926) 评论(0) 编辑 收藏 举报