python最短路径

dijkstra_text = """
{
    0:[(2,0.26),(4,0.38)],
    1:[(3,0.29)],
    2:[(7,0.34)],
    3:[(6,0.52)],
    4:[(7,0.37),(5,0.35)],
    5:[(1,0.32),(7,0.28),(4,0.35)],
    6:[(4,0.93),(0,0.58),(2,0.40)],
    7:[(3,0.39),(5,0.28)]
}

"""
import mst

MAX_VALUE = 2**31 - 1




g = eval(dijkstra_text)

mst.fill(g)


def dijkstra(g,source):
    where_from = dict()
    dist_to = dict()
    pq = mst.Min_PQ_(lambda x:x[-1])
    for v in g:
        dist_to[v] = MAX_VALUE
    dist_to[source] = 0
    pq.insert((source, 0))
    def relax(v):
        for e in g.get(v,[]):
            target,weight = e[1],e[-1]
            if dist_to[target]>dist_to[v]+weight:
                dist_to[target] = dist_to[v]+weight
                where_from[target]=v
                for i in range(0,len(pq.data)):
                    if pq.data[i][0] == target:
                        ## tuple 不可变
                        pq.data[i] = (target,dist_to[target])

                        break
                else:
                    pq.insert((target,dist_to[target]))

    while pq:
        ## 返回的是tuple需要用两个参数接收
        v,d = pq.remove()
        relax(v)
    return where_from

print(dijkstra(g,0))

posted @ 2016-07-13 00:28  Salaku  阅读(426)  评论(0编辑  收藏  举报