PTA 乙级 1047 编程团体赛 (20分) C/C++

 

 由于队伍数量有限（上限1000），直接创建队伍的数组，对应队伍成绩累加即可

C/C++

#include<iostream>

using namespace std;

int main() {
    int n = 0;
    /*队伍编号，队员编号，成绩*/
    int teamnum = 0, mem = 0, grad = 0;
    /*初始化队伍成绩*/
    int team[1001] = { 0 };
    cin >> n;
    for (int i = 0; i < n; ++i) {
        scanf("%d-%d %d", &teamnum, &mem, &grad);          //VS编辑器需要变为scanf_s
        team[teamnum] += grad;                        //对应队伍编号的队伍成绩进行累加
    }
    for (int i = 0; i < 1001; ++i) 
        if (team[i] > team[teamnum]) teamnum = i;    //求得最大值
    cout << teamnum << " " << team[teamnum];
    return 0;
}

Long time no see, 今日是水题，水水水！