UVa - 202 - Repeating Decimals

题目：https://vjudge.net/problem/UVA-202

https://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&page=show_problem&problem=138

#include <iostream>
#include <stdio.h>
#include <string.h>
using namespace std;

int main()
{
    int n,d,x,y;
    int ansx[3003],ansy[3003];
    while(scanf("%d%d",&n,&d)!=EOF){
        memset(ansx,0,sizeof(ansx));
        memset(ansy,0,sizeof(ansy));
        x=y=0;
        ansx[0]=n/d;
        ansy[0]=n%d;
        ansx[1]=ansy[0]*10/d;
        ansy[1]=ansy[0]*10%d;
//        cout<<ansx[1]<<endl<<ansy[1]<<endl;
        for(int i=2;i<3000;i++)
        {
            ansx[i]=ansy[i-1]*10/d;
            ansy[i]=ansy[i-1]*10%d;
//            cout<<"===="<<ansx[i]<<endl;
//            cout<<"===="<<ansy[i]<<endl;
            for(int j=1;j<i;j++)
            {
                if(ansx[i]==ansx[j]&&ansy[i]==ansy[j])
                {
                    x=j;
                    y=i;
                    break;
                }
            }
            if(x)
                break;
        }
        cout<<n<<"/"<<d<<" = "<<ansx[0]<<".";
        for(int i=1;i<x;i++)
        {
            cout<<ansx[i];
        }
        cout<<"(";
        if(y-x>50)
        {
            for(int i=x;i<x+50;i++)
                cout<<ansx[i];
            cout<<"...";
        }
        else
        {
            for(int i=x;i<y;i++)
            {
                cout<<ansx[i];
            }
        }
        cout<<")"<<endl;
        cout<<"   "<<y-x<<" = number of digits in repeating cycle"<<endl;
        cout<<endl;
    }
    return 0;
}

思路：

       辗转相除，数组存储每一位，前后对照找到两个数字相等并且余数相等的就说明循环节找到了