HDU1228 A + B

Problem Description
读入两个小于100的正整数A和B,计算A+B.
需要注意的是:A和B的每一位数字由对应的英文单词给出.
 


Input
测试输入包含若干测试用例,每个测试用例占一行,格式为"A + B =",相邻两字符串有一个空格间隔.当A和B同时为0时输入结束,相应的结果不要输出. 
 


Output
对每个测试用例输出1行,即A+B的值.
 


Sample Input
one + two = three four + five six = zero seven + eight nine = zero + zero =
 


Sample Output
3 90 96

#include<stdio.h>
#include<string.h>
int searchs(char a[]){
    char x[11][11]={"zero","one","two","three","four","five","six","seven","eight","nine"};
    int i;
    for(i=0;i<10;i++){
        if(strcmp(x[i],a)==0)
            break;
    }
    return i;
}
int main(){
    int a,b;
    char s[10];
    while(true){
        a=b=0;
        while(scanf("%s",s)&&strcmp(s,"+")){
            a=a*10+searchs(s);
        }
        while(scanf("%s",s)&&strcmp(s,"=")){
            b=b*10+searchs(s);
        }
        if(a==0&&b==0)
            break;
        printf("%d\n",a+b);
    }
    return 0;
}

strcmp(char s1[],char s2)

s1=s2 return 0

s1<s2 return 负数

s1>s2 return 正数