【Time系列五】个性时钟与秒表升级版

    从昨天到现在，一直在研究这个看起来超级简单的时钟。界面非常简洁大方。

虽然是简单，可是这个对齐的问题还是把我整得一塌糊涂。谁叫作者不解释清楚的。

    参考: http://bbs.fishc.com/thread-77638-1-1.html

    

    接下来，我们一步步解决。

 

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   步骤1 

    注意。这里是换行打印才能打印出这种图形的，这个字典储存的是列表，为啥储存的是列表呢？因为待会

一个数字，我们是要分上中下三个部分打印的。    

    这里的元素要尽可能对齐，因为这个程序最麻烦的就是要整齐的输出。第一个/位置0元素的笔画统一居中。

以0为例，位置0(一横)除了1和4之外,在其它数字都是给包围起来的，所以两边的空格其实是留给竖的！！!

 1 lcd = {
 2     0: [" _ ", "| |", "|_|"],
 3     1: ["   ", "  |", "  |"],
 4     2: [" _ ", " _|", "|_ "],
 5     3: [" _ ", " _|", " _|"],
 6     4: ["   ", "|_|", "  |"],
 7     5: [" _ ", "|_ ", " _|"],
 8     6: [" _ ", "|_ ", "|_|"],
 9     7: [" _ ", "  |", "  |"],
10     8: [" _ ", "|_|", "|_|"],
11     9: [" _ ", "|_|", " _|"]
12 }
13 
14 for num in lcd:
15     for i in lcd[num]:
16         print i

    如果输出的是这种整整齐齐的数字的话(代码是纵向输出的)，说明我们千辛万苦输入的列表元素是正确的。

 

     步骤2

    接上面的代码，完整版在下面。

 1 # coding: utf-8                                                             
 2 
 3 import time
 4 
 5 # 分别把时，分，秒，拆分成上中下三个部分并
 6 # 分别存储到一个空列表中(empty)
 7 
 8 def num2lcd(time):
 9    et = ["", "", ""]
10    shiwei = time / 10
11    gewei = time % 10
12 
13    for i in range(0, 3):
14        et[i] = lcd[shiwei][i] + lcd[gewei][i]
15     
16    return et
17 
18 # time.localtime()是输出当前日期的元组
19 # t.tm_hour是时，t.tm_min是分钟
20 # 这个函数最关键的部分是把之前分开的时，
21 # 分，秒的列表元素集合到一个列表中，最后统一打印出来。
22 
23 def clock():
24     t = time.localtime()
25     h = num2lcd(t.tm_hour)
26     m = num2lcd(t.tm_min)
27     s = num2lcd(t.tm_sec)
28 
29     output = [h[0] + m[0] + s[0], h[1] + m[1] + s[1], h[2] + m[2] + s[2]]
30     return output

    注意，这里的时间显示能否对齐完全取决于lcd字典是否对齐，每个值前面和后面的空格数量一定要控制好

 

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 1 # coding: utf-8                                                                                   2016/12/8
 2 
 3 import os, time
 4 
 5 # 这里在上面的基础上，每个列表的元素后面加
 6 # 多一个空格，让数字之间显示更美观
 7 
 8 lcd = {
 9     0: [" _  ", "| | ", "|_| "],
10     1: ["    ", "  | ", "  | "],
11     2: [" _  ", " _| ", "|_  "],
12     3: [" _  ", " _| ", " _| "],
13     4: ["    ", "|_| ", "  | "],
14     5: [" _  ", "|_  ", " _| "],
15     6: [" _  ", "|_  ", "|_| "],
16     7: [" _  ", "  | ", "  | "], 
17     8: [" _  ", "|_| ", "|_| "],
18     9: [" _  ", "|_| ", " _| "],
19 }
20 
21 # 分别把时，分，秒，拆分成上中下三个部分并
22 # 分别存储到一个空列表中(empty)
23 
24 def num2lcd(time):
25    et = ["", "", ""]
26    shiwei = time / 10
27    gewei = time % 10
28 
29    for i in range(0, 3):
30        et[i] = lcd[shiwei][i] + lcd[gewei][i]
31     
32    return et
33 
34 # time.localtime()是输出当前日期的元组
35 # t.tm_hour是时，t.tm_min是分钟
36 # 这个函数最关键的部分是把之前分开的时，
37 # 分，秒的列表元素集合到一个列表中，最后统一打印出来。
38 
39 def clock():
40     t = time.localtime()
41     h = num2lcd(t.tm_hour)
42     m = num2lcd(t.tm_min)
43     s = num2lcd(t.tm_sec)
44 
45     output = [h[0] + " " + m[0] + " " + s[0], h[1] + "." + m[1] + "." + s[1], h[2] + "." + m[2] + "." + s[2]]
46     return output
47 
48 
49 while True:
50     for i in clock():
51         print i
52     time.sleep(1) 
53     os.system("cls")
时钟完整版

    由于在时和分，分和秒之间加了冒号，而每个时h[0]和分m[0]，分m[0]和秒s[0]之间距离是一定的，

由于冒号自身占用1个空格，所以后面的会变成这样。因此要在h[0]的m[0]，m[0]和s[0]之间加上空格。

1 output = [h[0] + " " + m[0] + " " + s[0], h[1] + "." + m[1] + "." + s[1], h[2] + "." + m[2] + "." + s[2]]

 ----------------------------------------------------------------------------------------------------------------------------

  秒表的同理类似。这里就不再介绍了，直接附上代码。

# coding: utf-8

import os, sys, time

lcd = {
    0: [" _  ", "| | ", "|_| "],
    1: ["    ", "  | ", "  | "],
    2: [" _  ", " _| ", "|_  "],
    3: [" _  ", " _| ", " _| "],
    4: ["    ", "|_| ", "  | "],
    5: [" _  ", "|_  ", " _| "],
    6: [" _  ", "|_  ", "|_| "],
    7: [" _  ", "  | ", "  | "],
    8: [" _  ", "|_| ", "|_| "],
    9: [" _  ", "|_| ", " _| "]
}

def num2lcd(time):
    et = ["", "", ""]
    shiwei = time / 10
    gewei = time % 10

    for i in range(0, 3):
        et[i] = lcd[shiwei][i] + lcd[gewei][i]

    return et

def clock(minute, second):
    m = num2lcd(minute)
    s = num2lcd(second)

    output = [m[0] + " " + s[0], m[1] + "." + s[1], m[2] + "." + s[2]]

    return output

sec = 0
while True:
        sec += 1
        m = sec / 60
        s = sec % 60

        for i in clock(m, s): 
            print i

        time.sleep(1)
        os.system("cls")

    一般来说，当需要输出时间时，用求余符号%来求出分和秒是比较简便的。或者大家也可

以看看下面这一种。是用for循环在1和60之间循环递增的。选择自己喜欢的一种即可。

 1 # coding: utf-8
 2 
 3 import os, sys, time
 4 
 5 lcd = {
 6     0: [" _  ", "| | ", "|_| "],
 7     1: ["    ", "  | ", "  | "],
 8     2: [" _  ", " _| ", "|_  "],
 9     3: [" _  ", " _| ", " _| "],
10     4: ["    ", "|_| ", "  | "],
11     5: [" _  ", "|_  ", " _| "],
12     6: [" _  ", "|_  ", "|_| "],
13     7: [" _  ", "  | ", "  | "],
14     8: [" _  ", "|_| ", "|_| "],
15     9: [" _  ", "|_| ", " _| "]
16 }
17 
18 def num2lcd(time):
19     et = ["", "", ""]
20     shiwei = time / 10
21     gewei = time % 10
22 
23     for i in range(0, 3):
24         et[i] = lcd[shiwei][i] + lcd[gewei][i]
25 
26     return et
27 
28 def clock(minute, second):
29     m = num2lcd(minute)
30     s = num2lcd(second)
31 
32     output = [m[0] + " " + s[0], m[1] + "." + s[1], m[2] + "." + s[2]]
33 
34     return output
35 
36 minute = 0
37 while True:
38     for sec in range(1, 61):    
39         if sec == 60:
40             sec = 0                       # 记得到了第60秒时秒要清零哦
41             minute += 1                   # 同时分钟要 +1
42                                                      
43         for i in clock(minute, sec):
44             print i
45 
46         time.sleep(1)
47         os.system("cls")
lcd秒表

 

posted @ 2016-12-08 23:25  坏小孩D_R  阅读(357)  评论(0)  编辑  收藏  举报