[LeetCode]Search a 2D Matrix

Write an efficient algorithm that searches for a value in an m x n matrix. This matrix has the following properties:

 

  • Integers in each row are sorted from left to right.
  • The first integer of each row is greater than the last integer of the previous row.

 

For example,

Consider the following matrix:

[
  [1,   3,  5,  7],
  [10, 11, 16, 20],
  [23, 30, 34, 50]
]

Given target = 3, return true.

class Solution {
public:
    bool searchMatrix(vector<vector<int> > &matrix, int target) {
        int row=matrix.size();
        int col=matrix[0].size();
        int i=0;
        int j=col-1;
        while(i<row&&j>=0)
        {
            int temp=matrix[i][j];
            if(temp==target) return true;
            else if(temp>target) j--;
            else i++;
        }
        return false;
    }
};

  

posted @ 2014-01-14 15:13  七年之后  阅读(197)  评论(0编辑  收藏  举报