Codeforces Round #321 (Div. 2) A. Kefa and First Steps【暴力/dp/最长不递减子序列】
Kefa decided to make some money doing business on the Internet for exactly n days. He knows that on the i-th day (1 ≤ i ≤ n) he makes ai money. Kefa loves progress, that's why he wants to know the length of the maximum non-decreasing subsegment in sequence ai. Let us remind you that the subsegment of the sequence is its continuous fragment. A subsegment of numbers is called non-decreasing if all numbers in it follow in the non-decreasing order.
Help Kefa cope with this task!
The first line contains integer n (1 ≤ n ≤ 105).
The second line contains n integers a1, a2, ..., an (1 ≤ ai ≤ 109).
Print a single integer — the length of the maximum non-decreasing subsegment of sequence a.
6
2 2 1 3 4 1
3
3
2 2 9
3
In the first test the maximum non-decreasing subsegment is the numbers from the third to the fifth one.
In the second test the maximum non-decreasing subsegment is the numbers from the first to the third one.
【代码】:
#include <bits/stdc++.h> using namespace std; const int N = 1e5+100; int n,a[N],ans,maxn; int main() { cin>>n; for(int i=0;i<n;i++)//0开始 cin>>a[i]; for(int i=1;i<=n;i++)//1开始 { if(a[i]>=a[i-1]) { ans++; maxn=max(maxn,ans); } else ans=0; } cout<<maxn+1<<endl; return 0; }