1953 Problem B #103. 子串查找

#include<stdio.h>
#include<string.h>
main()
{
char a[100],b[100];
int n,k,i;
gets(a);
gets(b);
n=0;
for(k=0;k<=strlen(a)-strlen(b);k++)
{
for(i=0;b[i]!=0;i++)
if(b[i]!=a[k+i]) break;
if(b[i]==0) n=n+1;
}
printf("%d\n",n);
}
/*
A Not allowed system call: runid:292141 :使用了系统禁止的操作系统调用,看看是否越权访问了文件或进程等资源
buffer overflow detected:缓冲区溢出,检查是否有字符串长度超出数组的情况*/ #include <iostream> #include <algorithm> #include <string> using namespace std; int main() { string a,b; cin>>a>>b; int res=0; for(int i=0;i<a.length()-b.length()+1;i++) { if(b == a.substr(i, b.length())) { res++; } } cout<<res<<endl; return 0; } #include "stdafx.h" #include "string.h" int main(int argc, char* argv[]) { char strA[80],strB[80]; int count = 0; scanf("%s", &strA); scanf("%s", &strB); char *p; p = strstr(strA, strB); while (p) { count++; p++; p = strstr(p, strB); } printf("%d/n", count); return 0; }/*Segmentation fault:段错误,检查是否有数组越界,指针异常,访问到不应该访问的内存区域*/ // string A("ababa"); string B("aba"); string::size_type pos = 0; int cnt = 0; while ((pos = A.find_first_of(B, pos)) != string::npos) { ++cnt; ++pos; }

  

posted @ 2017-08-14 14:39  Roni_i  阅读(195)  评论(0编辑  收藏  举报