Codeforces 1191B Tokitsukaze and Mahjong

题目链接：http://codeforces.com/problemset/problem/1191/B

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题意：类似于麻将，三个一样花色一样数字的，或者三个同花顺就赢了，新抽的能当任何类型，问至少几个。

思路：分类判断即可。

AC代码：

#include<bits/stdc++.h>
using namespace std;
string a, b, c;
bool check(int x, int y, int z){
    if (x == (y + z) / 2 && abs(y - z) == 2) return true;
    if (y == (x + z) / 2 && abs(x - z) == 2) return true;
    if (z == (y + x) / 2 && abs(y - x) == 2) return true;
    return false;
}//同花顺检测
int main() {
    //freopen("in.txt", "r", stdin);
    ios::sync_with_stdio(false), cin.tie(0);
    cin >> a >> b >> c;
    int x = a[0] - '0';
    int y = b[0] - '0';
    int z = c[0] - '0';
    if (a[1] == b[1] && b[1] == c[1]) 
        if ((x == y && y == z) || check(x, y, z)) return cout << 0, 0;
        else if (abs(x - y) <= 2 || abs(z - y) <= 2 || abs(x - z) <= 2) cout << 1 << endl;
        else cout << 2 << endl;
    else if (a[1] == b[1]) 
        if (x == y || abs(x - y) <= 2) cout << 1 << endl;
        else cout << 2 << endl;
    else if (b[1] == c[1])
        if (z == y || abs(z - y) <= 2) cout << 1 << endl;
        else cout << 2 << endl;
    else if (a[1] == c[1])
        if (x == z || abs(x - z) <= 2) cout << 1 << endl;
        else cout << 2 << endl;
    else cout << 2 << endl;
    return 0;
}