实验4 数组

实验任务1

 

<1>

#include <stdio.h> 
#define N 4 
int main() 
{ 
    int a[N] = {2, 0, 2, 2}; 
    char b[N] = {'2', '0', '2', '2'}; 
    int i; 
    printf("sizeof(int) = %d\n", sizeof(int)); 
    printf("sizeof(char) = %d\n", sizeof(char)); 
    printf("\n"); // 输出数组a中每个元素的地址、值 
    for (i = 0; i < N; ++i) printf("%p: %d\n", &a[i], a[i]); 
    printf("\n"); // 输出数组b中每个元素的地址、值 
    for (i = 0; i < N; ++i) printf("%p: %c\n", &b[i], b[i]); 
    printf("\n"); // 输出数组名a和b对应的值 
    printf("a = %p\n", a); 
    printf("b = %p\n", b); 
    return 0; 
}

 

（1）：不是，4个；

（2）：是，1个；

（3）：一样，一样。

 

<2>

#include <stdio.h> 
#define N 2 
#define M 3 
int main() 
{ 
    int a[N][M] = {{1, 2, 3}, {4, 5, 6}}; 
    char b[N][M] = {{'1', '2', '3'}, {'4', '5', '6'}}; 
    int i, j; // 输出二维数组a中每个元素的地址和值 
    for (i = 0; i < N; ++i) 
        for (j = 0; j < M; ++j) printf("%p: %d\n", &a[i][j], a[i][j]); 
    printf("\n"); // 输出二维数组a中每个元素的地址和值 
    for (i = 0; i < N; ++i) 
        for (j = 0; j < M; ++j) printf("%p: %c\n", &b[i][j], b[i][j]); 
    return 0; 
}

（1）：是，4个；

（2）：是，1个。

 

实验任务2

#include <stdio.h> 
int days_of_year(int year, int month, int day);
int main()
{ 
    int year, month, day; 
    int days; 
    while(scanf("%d%d%d", &year, &month, &day) != EOF)
    {
        days = days_of_year(year, month, day);
        printf("%4d-%02d-%02d是这一年的第%d天.\n\n", year, month, day, days); 
    }
return 0; 
}
int days_of_year(int year, int month, int day)
{
    int s=0;
    int days_of_each_month[13]={0,31,29,31,30,31,30,31,31,30,31,30,31};
    if(year%400==0||year%4==0&&year%100!=0) days_of_each_month[2]=28;
    for(int i=1;i<month;i++) s+=days_of_each_month[i];
    return(s+day);
} 

 

 

实验任务3

#include <stdio.h> 
#define N 5
void input(int x[], int n); 
void output(int x[], int n); 
double average(int x[], int n); 
void sort(int x[], int n); 
int main() 
{ 
    int scores[N]; 
    double ave; 
    printf("录入%d个分数:\n", N); 
    input(scores, N); 
    printf("\n输出课程分数: \n"); 
    output(scores, N); 
    printf("\n课程分数处理: 计算均分、排序...\n"); 
    ave = average(scores, N); 
    sort(scores, N); 
    printf("\n输出课程均分: %.2f\n", ave); 
    printf("\n输出课程分数(高->低):\n"); 
    output(scores, N); 
    return 0; 
}
void input(int x[], int n) 
{ 
    int i; 
    for(i=0; i<n; ++i) 
    scanf("%d", &x[i]); 
}
void output(int x[], int n) 
{ 
    int i; 
    for(i=0; i<n; ++i) 
    printf("%d ", x[i]); 
    printf("\n"); 
}
double average(int x[], int n)
{    
    double s=0;
    for(int i=0;i<n;i++) s+=x[i];
    return(s/n);
}
void sort(int x[], int n)
{
    int m;
    for(int i=0;i<n;i++)
    {
        for(int j=i+1;j<n;j++) 
        {
            if(x[j]>x[i])
            {    m=x[i];
                x[i]=x[j];
                x[j]=m;
            }
        
        }
    }
}

 

实验任务4

#include <stdio.h> 
void dec2n(int x, int n);
int main() 
{ 
    int x; 
    printf("输入一个十进制整数: "); 
    scanf("%d", &x); 
    dec2n(x, 2);
    dec2n(x, 8);
    dec2n(x, 16);
    return 0; 
}
void dec2n(int x, int n) 
{
    int t,i;
    int rs[1000];
    while(x!=0)
    {
        t=x%n;
        rs[i]=t;
        x=x/n;
        i++;
    }
    for(int j=i-1;j>=0;j--)
    {
        if(rs[j]>9) printf("%c",rs[j]-10+'A');
        else printf("%d",rs[j]);
    }
    printf("\n");
}

 

实验任务5

#include<stdio.h>
int main()
{
    int i,j,k,n;
    printf("Enter n: ");
    while(scanf("%d",&n)!= EOF)
    {
        for(i=1;i<=n;i++)
        {
            for(j=1;j<=n;j++)
            {
               k=i>j?j:i;
               printf("%3d",k);
            }
            printf("\n");
        }
        printf("Enter n: ");
    }
    return 0;
}

 

实验任务6

#include <stdio.h> 
#define N 80 
int main() 
{ 
    char views1[N] = "hey, c, i hate u."; 
    char views2[N] = "hey, c, i love u.";
    char t;
    printf("original views:\n");
    printf("views1:");
    puts(views1);
    printf("views2:");
    puts(views2);
    for (int i = 0; views1[i]!= '\0'; i++)
    {
        t = views1[i];
        views1[i] = views2[i];
        views2[i] = t;
    }
    printf("\nswapping...\n\n");
    printf("views1:");
    puts(views1);
    printf("views2:");
    puts(views2); 
    return 0;
}

 

实验任务7

#include <stdio.h>
#include <string.h>
#define N 5
#define M 20
void bubble_sort(char str[][M], int n); 
int main()
{
    char name[][M] = {"Bob", "Bill", "Joseph", "Taylor", "George"};
    int i;
    printf("输出初始名单:\n");
    for (i = 0; i < N; i++)
    printf("%s\n", name[i]);
    
    printf("\n排序中...\n");
    bubble_sort(name, N); 
    
    printf("\n按字典序输出名单:\n");
    for (i = 0; i < N; i++)
    printf("%s\n", name[i]);
    return 0;
}
void bubble_sort(char str[][M],int n)
{
    char r[M];
    for(int i=0;i<N;i++)
    {
        for(int j=0;j<N-1;j++)
        { 
            if(strcmp(str[j],str[j+1])>0)
            {
                strcpy(r,str[j]);
                strcpy(str[j],str[j+1]);
                strcpy(str[j+1],r);
            }
        }
    }        
}