4Sum

Given an array S of n integers, are there elements abc, and d in S such that a + b + c + d = target? Find all unique quadruplets in the array which gives the sum of target.

Note:

  • Elements in a quadruplet (a,b,c,d) must be in non-descending order. (ie, a ≤ b ≤ c ≤ d)
  • The solution set must not contain duplicate quadruplets.

 

    For example, given array S = {1 0 -1 0 -2 2}, and target = 0.

    A solution set is:
    (-1,  0, 0, 1)
    (-2, -1, 1, 2)
    (-2,  0, 0, 2)

解题思路:

  4个指针, 前两个指针双循环遍历数组,第三个指针放在第二个指针之后,第四个指针放在末尾,求和和target比较,如果 sum > target 最后一个指针--, 如果sum < target 第三个指针++; 相等先判断是否是重复的(hashset),如果不是添加到result中去;

 1 public class Solution {
 2     public ArrayList<ArrayList<Integer>> fourSum(int[] num, int target) {
 3         Arrays.sort(num);
 4         ArrayList<ArrayList<Integer>> result = new ArrayList<ArrayList<Integer>>();
 5         HashSet<ArrayList<Integer>> set = new HashSet<ArrayList<Integer>>();
 6         int len = num.length;
 7         for(int i = 0; i< len; i++){
 8             for(int j = i+1; j < len; j++){
 9                 int k = j+1;
10                 int l = len-1;
11                 
12                 while(k < l){
13                   int sum = num[i]+num[j]+num[k]+num[l];
14                         
15                         if(sum < target){
16                             k++;
17                         }else if(sum > target){
18                             l--;
19                         }else {
20                             ArrayList<Integer> output = new ArrayList<Integer>();
21                             output.add(num[i]);
22                             output.add(num[j]);
23                             output.add(num[k]);
24                             output.add(num[l]);
25                             if(! set.contains(output)){
26                                 set.add(output);
27                                 result.add(output);
28                             }
29                             k++;
30                             l--;
31                         }      
32                 }   
33             }
34         }
35         
36         return result;
37         
38     }
39 }
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posted @ 2014-02-13 13:07  Razer.Lu  阅读(260)  评论(0编辑  收藏  举报