摘要: 目前总分:100 + 100 + 50 + 0 + 8 + 0 + 50 = 308 A (100 pts) \[f^k(x) = \dfrac{x^{2^k}}{2^{2^k-2}}=\left(\dfrac{x}{2}\right)^{2^k-2} \times x^2 \]当 \(x = 2\ 阅读全文
posted @ 2024-04-13 19:29 CountingGroup 阅读(28) 评论(0) 推荐(0) 编辑