python-多线程趣味

假设一个程序员,想听歌,但是又想敲代码,于是又:

我听完歌就去敲代码:

#! /usr/bin/env python
#coding=utf-8

import time

def matter1(music):
    print("我想听这些歌")
    
    for i in range(0,len(music)):
        print("" + str(i + 1) + "首歌是:" + str(music[i]))
        
        #当前时间
        print(time.strftime('%Y%H%M%S',time.localtime()))
        #假设每一首歌曲的时间是2秒
        time.sleep(2)
        print("切换下一首歌...")

def matter2(number):
    print("我在敲代码")
    
    j = 0
    while j < number:
        print("我准备写入第" + str(j +1) + "行代码")
        j = j + 1
        #当前时间
        print(time.strftime('%Y%H%M%S',time.localtime()))
        #假设每写一行代码的时间为1s
        time.sleep(1)
        print("写下一行代码...")
        
if __name__ == '__main__':
    
    start = time.time()
    
    #设定我要听的个为
    music = ['music1','music2','music3']
    #开始听歌
    matter1(music)
    
    #设定敲代码的行数
    number = 5
    #开始敲代码
    matter2(number)
    
    end = time.time()
    print("完成的时间:",str(end - start))

结果:

完成的时间: 11.00062894821167

 

可以改成,一边敲代码一边听歌,那么设计一个多线程,可以让他们同时进行

#! /usr/bin/env python
#coding=utf-8

import time
import threading

def matter1(music):
    print("我想听歌!!!")
    
    for i in range(0,len(music)):
        print("" + str(i+1) + "首歌是:" + str(music[i]))
        
        #当前时间是
        print(time.strftime('%Y%H%M%S',time.localtime()))
        
        #假设每一首歌曲的时间是2s
        time.sleep(2)
        
        print("切换下一首歌...")
        
def matter2(number):
    print("我在敲代码!!!")
    
    j = 0
    while j < number:
        print("我准备写入第" + str(j+1) + "行代码")
        j = j+1
        
        #当前时间是
        print(time.strftime('%Y%H%M%S',time.localtime()))
        
        #假设每写一行代码的时间为1s
        time.sleep(1)
        
        print("写下一行代码...")

if __name__ == '__main__':
    #设定我要听的歌为
    music = ["music1","music2","music3"]
    
    #设定我要敲代码的行数
    number = 5
    
    threads = []
    
    thing1 = threading.Thread(target=matter1,args=(music,))
    threads.append(thing1)
    
    thing2 = threading.Thread(target=matter2,args=(number,))
    threads.append(thing2)
    
    #开始时间
    startTime = time.time()
    
    #写个for让两件事情都进行
    for thing in threads:
        #setDaemon为主线程启动了线程matter1和matter2
        #启动也就是相当于执行了这个for循环
        thing.setDaemon(True)
        thing.start()
        
    #为了防止子线程还没结束主线程就结束的意外情况,在程序里面加个join
    #子进程没结束前,主线程会被卡在这里
    thing1.join()
    thing2.join()
    
    #结束时间
    endTime = time.time()
    print("完成的时间为:",str(endTime-startTime))

结果:

完成的时间为: 6.000343084335327

 

封装成类的形式

#! /usr/bin/env python
#coding=utf-8

import time
import threading

class MyThread(threading.Thread):
    def __init__(self,func,args,name=''):
        threading.Thread.__init__(self)
        self.name = name
        self.func = func
        self.args = args
        
    def run(self):
        #某某线程要开始了
        print(self.name + "开始了#######")
        
        if self.name == "听歌线程":
            matter1(music)
        elif self.name == "打码线程":
            matter2(number)
        print(self.name + "结束了########")
    
def matter1(music):
    for i in range(0,len(music)):
        print("" + str(i+1) + "首歌是:" + str(music[i]))
        #假设每一首歌曲的时间是2s
        time.sleep(2)
        print("切换下一首歌...")
            
def matter2(number):
    j = 0
    while j < number:
        print("我准备写入第" + str(j+1) + "行代码")
        j = j+1
        #假设每一行代码的时间为1s
        time.sleep(1)
        print("写下一行代码...")
            
if __name__ == '__main__':
    #设定我要听的歌曲为
    music = ['music1','music2','music3']
    
    #设定我要打码的行数
    number = 5
    
    #开始时间
    start = time.time()
    
    thing1 = MyThread(matter1,music,"听歌线程")
    thing2 = MyThread(matter2,number,"打码线程")
    
    thing1.start()
    thing2.start()
    
    thing1.join()
    thing2.join()
    
    #结束时间
    end = time.time()
    print("完成的时间为:",str(end - start))

结果:

完成的时间为: 6.001343011856079

posted @ 2017-10-24 17:46  R-Bear  阅读(323)  评论(0编辑  收藏  举报