js 身份证校验

IdentityCodeValid(code) {
let city = {
11: "北京",
12: "天津",
13: "河北",
14: "山西",
15: "内蒙古",
21: "辽宁",
22: "吉林",
23: "黑龙江 ",
31: "上海",
32: "江苏",
33: "浙江",
34: "安徽",
35: "福建",
36: "江西",
37: "山东",
41: "河南",
42: "湖北 ",
43: "湖南",
44: "广东",
45: "广西",
46: "海南",
50: "重庆",
51: "四川",
52: "贵州",
53: "云南",
54: "西藏 ",
61: "陕西",
62: "甘肃",
63: "青海",
64: "宁夏",
65: "新疆",
71: "台湾",
81: "香港",
82: "澳门",
91: "国外 "
};
let tip = "";
let pass = true;

if (!code || !/^\d{6}(18|19|20)?\d{2}(0[1-9]|1[0-2])(0[1-9]|[12]\d|3[01])\d{3}(\d|X)$/i.test(code)) {
tip = "身份证号格式错误";
pass = false;
} else if (!city[code.substr(0, 2)]) {
tip = "地址编码错误";
pass = false;
} else {
//18位身份证需要验证最后一位校验位
if (code.length == 18) {
code = code.split('');
//∑(ai×Wi)(mod 11)
//加权因子
let factor = [7, 9, 10, 5, 8, 4, 2, 1, 6, 3, 7, 9, 10, 5, 8, 4, 2];
//校验位
let parity = [1, 0, 'X', 9, 8, 7, 6, 5, 4, 3, 2];
let sum = 0;
let ai = 0;
let wi = 0;
for (let i = 0; i < 17; i++) {
ai = code[i];
wi = factor[i];
sum += ai * wi;
}
let last = parity[sum % 11];
if (parity[sum % 11] != code[17]) {
tip = "校验位错误";
pass = false;
}
}
}
if (!pass) {
alert(tip + ',请输入合法的身份证号码');
    }
return pass;
},

posted on 2020-11-09 18:27  →萩.c  阅读(56)  评论(0编辑  收藏  举报

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