FourElements

\(A(x)=\sum x^{a_i}=\frac{x^{l_i}-x^{r_i+1}}{1-x}\)

\[F=\frac{1}{24}(\\ A(x)^4-\\ 6\cdot A(x)^2A(x^2)+\\ 3\cdot A(x^2)^2+\\ 8\cdot A(x^3)A(x)-\\ 6A(x^4) \\) \]

\[Answer=[x^s] F \]

\[[x^t][(\frac{1}{1-x})^z]={t+z-1\choose z-1},z\geq 1,t\geq 0 \]

\(B(x)=A(x)^2(1-x)^2\)

\[A(x)^4=\sum_{\alpha+\beta\leq s} [[x^\alpha]B(x)]\cdot[[x^\beta]B(x)]{s-\alpha-\beta+3\choose 3}\\ {s-\alpha-\beta+3\choose 3}=(s-\alpha-\beta+3)*(s-\alpha-\beta+2)*(s-\alpha-\beta+1)\div6\\ =\sum coef_{i,j}\alpha^i\beta^j[[x^\alpha]B(x)]\cdot[[x^\beta]B(x)]\\ =\sum coef_{i,j}sum[i]\cdot sum[j] \]

posted @ 2021-12-19 23:04  WWW~~~  阅读(43)  评论(0编辑  收藏  举报