python路径拼接os.path.join()函数的用法
python路径拼接os.path.join()函数的用法
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os.path.join()函数：连接两个或更多的路径名组件
1.如果各组件名首字母不包含’/’，则函数会自动加上
2.如果有一个组件是一个绝对路径，则在它之前的所有组件均会被舍弃
3.如果最后一个组件为空，则生成的路径以一个’/’分隔符结尾
Demo1
import os
Path1 = 'home'
Path2 = 'develop'
Path3 = 'code'
Path10 = Path1 + Path2 + Path3
Path20 = os.path.join(Path1,Path2,Path3)
print ('Path10 = ',Path10)
print ('Path20 = ',Path20)
输出
Path10 = homedevelopcode
Path20 = home\develop\code
Demo2
import os
Path1 = '/home'
Path2 = 'develop'
Path3 = 'code'
Path10 = Path1 + Path2 + Path3
Path20 = os.path.join(Path1,Path2,Path3)
print ('Path10 = ',Path10)
print ('Path20 = ',Path20)
输出
Path10 = /homedevelopcode
Path20 = /home\develop\code
Demo3
import os
Path1 = 'home'
Path2 = '/develop'
Path3 = 'code'
Path10 = Path1 + Path2 + Path3
Path20 = os.path.join(Path1,Path2,Path3)
print ('Path10 = ',Path10)
print ('Path20 = ',Path20)
输出
Path10 = home/developcode
Path20 = /develop\code
Demo4
import os
Path1 = 'home'
Path2 = 'develop'
Path3 = '/code'
Path10 = Path1 + Path2 + Path3
Path20 = os.path.join(Path1,Path2,Path3)
print ('Path10 = ',Path10)
print ('Path20 = ',Path20 )
输出
Path10 = homedevelop/code
Path20 = /code
