[bzoj1452][JSOI2009]Count(树状数组)

1452: [JSOI2009]Count

Time Limit: 10 Sec  Memory Limit: 64 MB
Submit: 2057  Solved: 1216
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Description

Input

Output

Sample Input



Sample Output

1
2

HINT

 

 

Source

 

裸得不能再裸了

暴力100个二维即可

 1 #include<stdio.h>
 2 #include<stdlib.h>
 3 #include<string.h>
 4 #define LL long long
 5 int n,m;
 6 int lb(int x){
 7     return x&(-x);
 8 }
 9 int bit[110][310][310];
10 int gra[310][310];
11 int q(int v,int x,int y){
12     int ans=0;
13     for(int i=x;i;i-=lb(i)){
14         for(int j=y;j;j-=lb(j)){
15             ans+=bit[v][i][j];
16         }
17     }
18     return ans;
19 }
20 int c(int v,int num,int x,int y){
21     for(int i=x;i<=n;i+=lb(i)){
22         for(int j=y;j<=n;j+=lb(j)){
23             bit[v][i][j]+=num;
24         }
25     }
26     return 0;
27 }
28 int main(){
29     scanf("%d %d",&n,&m);
30     for(int i=1;i<=n;i++){
31         for(int j=1;j<=m;j++){
32             int x;
33             scanf("%d",&x);
34             gra[i][j]=x;
35             c(x,1,i,j);
36         }
37     }
38     int Q;
39     scanf("%d",&Q);
40     while(Q--){
41         int op;
42         scanf("%d",&op);
43         if(op==1){
44             int x,y,v;
45             scanf("%d %d %d",&x,&y,&v);
46             c(v,1,x,y);
47             c(gra[x][y],-1,x,y);
48             gra[x][y]=v;
49         }else{
50             int x1,y1,x2,y2,v;
51             scanf("%d %d %d %d %d",&x1,&x2,&y1,&y2,&v);
52             x1--;
53             y1--;
54             printf("%d\n",q(v,x2,y2)-q(v,x2,y1)-q(v,x1,y2)+q(v,x1,y1));
55         }
56     }
57     return 0;
58 }
View Code

 

posted @ 2016-09-15 00:47  Pumbit-Legion  阅读(224)  评论(0)  编辑  收藏  举报