hdu 5012(bfs)

题意:给你2个 骰子,让你通过翻转使第一个变成第二个,求最少翻转数

思路:bfs


#include<cstdio>
#include<iostream>
#include<cstring>
#include<cstdlib>
#include<cmath>
#include<algorithm>
#include<string>
#include<map>
#include<set>
#include<vector>
#include<queue>
#include<stack>
using namespace std;
typedef long long ll;

struct node
{
    int arr[6];
    int ci;
};

int vis[1000000];
int len;
bool ju(node a, node b)
{
    for (int i = 0; i < 6; i++)
        if (a.arr[i] != b.arr[i])
            return false;
    return true;
}

bool sol(node c)
{
    int num = 0;
    for (int i = 0; i < 6; i++)
    {
        num = num * 10 + c.arr[i];
    }
    if(vis[num])
        return false;
    else{
        vis[num] = 1;
        return true;
    }
}

node turn(node a, int i)
{
    node c;
    if (i == 1)
    {
        c.arr[0] = a.arr[3];
        c.arr[1] = a.arr[2];
        c.arr[2] = a.arr[0];
        c.arr[3] = a.arr[1];
        c.arr[4] = a.arr[4];
        c.arr[5] = a.arr[5];
    }
    if (i == 2)
    {
        c.arr[0] = a.arr[2];
        c.arr[1] = a.arr[3];
        c.arr[2] = a.arr[1];
        c.arr[3] = a.arr[0];
        c.arr[4] = a.arr[4];
        c.arr[5] = a.arr[5];
    }
    if (i == 3)
    {
        c.arr[0] = a.arr[5];
        c.arr[1] = a.arr[4];
        c.arr[2] = a.arr[2];
        c.arr[3] = a.arr[3];
        c.arr[4] = a.arr[0];
        c.arr[5] = a.arr[1];
    }
    if (i == 4)
    {
        c.arr[0] = a.arr[4];
        c.arr[1] = a.arr[5];
        c.arr[2] = a.arr[2];
        c.arr[3] = a.arr[3];
        c.arr[4] = a.arr[1];
        c.arr[5] = a.arr[0];
    }
    return c;
}

int main()
{
    node p1,p2;
    while(scanf("%d%d%d%d%d%d",&p1.arr[0],&p1.arr[1],&p1.arr[2],&p1.arr[3],&p1.arr[4],&p1.arr[5]) != EOF)
    {
        scanf("%d%d%d%d%d%d",&p2.arr[0],&p2.arr[1],&p2.arr[2],&p2.arr[3],&p2.arr[4],&p2.arr[5]);
        memset(vis,0,sizeof(vis));
        queue<node> q;
        len = p1.ci = p2.ci = 0;
        q.push(p1);
        int flag = 0;
        while(!q.empty())
        {
            node tmp = q.front();
            q.pop();
            if(ju(tmp,p2))
            {
                printf("%d\n",tmp.ci);
                flag = 1;
                break;
            }
            for(int i = 1; i <= 4; i++)
            {
                node c = turn(tmp,i);
                if(sol(c))
                {
                    c.ci = tmp.ci + 1;
                    q.push(c);
                }
            }
        }
        if(!flag)
            printf("-1\n");
    }
    return 0;
}

  

posted @ 2015-09-09 16:23  Przz  阅读(158)  评论(0编辑  收藏  举报