Python 正则表达式

 1 #!/usr/bin/env python
 2 #-*- coding:utf-8 -*-
 3 import re
 4 
 5 #match 从开头匹配
 6 a = re.match("abc","abcdef")
 7 print(a)
 8 print(a.group())
 9 
10 a = re.match("abc","cabcdef")
11 print(a)
12 
13 c = re.match("[0-9][0-9]","78d6ef")
14 print(c)
15 print(c.group())
16 
17 c = re.match("[0-9]{0,10}","78d6ef")#匹配0到10次
18 print(c.group())
19 
20 c = re.match("[0-9]{2}","7890d6ef")#匹配两次
21 print(c.group())
22 
23 #findall 匹配所有
24 d = re.findall("[0-9]{1,10}","123abcde45eg")
25 print(d)
26 
27 d = re.findall("[a-zA-Z]{1,10}","123abcde45eg")
28 print(d)
29 
30 #匹配任意字符
31 e = re.findall(".*","123456abcde")
32 print(e)
33 
34 #搜索
35 f = re.search("\d+","75_46.5 4a~bc6@def")
36 print("f is {0}".format(f.group()))
37  
38 f = re.search("^\d+$","752343445")#匹配以数字开头和以数字结尾
39 print("f is {0}".format(f.group()))
40 
41 #替换
42 g = re.sub("\d+","|","adf75_46.5 4a~bc6@def",count=2)#将匹配的数字替换成|,替换两个,若没有count则全部替换
43 print('g is {0}'.format(g))

 

<_sre.SRE_Match object; span=(0, 3), match='abc'>
abc
None
<_sre.SRE_Match object; span=(0, 2), match='78'>
78
78
78
['123', '45']
['abcde', 'eg']
['123456abcde', '']
f is 75
f is 752343445
g is adf|_|.5 4a~bc6@def

posted @ 2018-06-27 22:28  Presley  阅读(132)  评论(0编辑  收藏  举报