[8.3] Magic Index
A magic index in an array A[0...n-1] is defined to be an index such that A[i] = i. Given a sorted array of distinct integers, write a method to find a magic index, if one exists, in array A.
FOLLOW UP
What if the values are not distinct?
public int getMagicIndex(int[] inputs) { return helper(0, inputs.length - 1, inputs); } private int helper(int start, int end, int[] inputs) { if(end < start) return -1; int mid = (end - start) / 2 + start; if(mid == inputs[mid]) { return mid; } else if (mid > inputs[mid]) { return helper(mid + 1, end, inputs); } else { return helper(start, mid - 1, inputs); } }
Follow Up: 看答案的
/** * * A magic index in an array A[0...n-1] is defined to be an index such that A[i] = i. * Given a sorted array of distinct integers, write a method to find a magic index, if one exists, in array A. * * FOLLOW UP * What if the values are not distinct? * */ public static void main(String[] args) { // TODO Auto-generated method stub int[] inputs = {-11, -9, -3, -3, 4, 6, 7, 8, 9, 10, 11, 12, 13, 16}; System.out.println(getMagicIndex(inputs)); } public static int getMagicIndex(int[] inputs) { return helper(0, inputs.length - 1, inputs); } private static int helper(int start, int end, int[] inputs) { if(end < start) return -1; int midIndex = (end - start) / 2 + start; int midValue = inputs[midIndex]; if(midIndex == midValue) { return midIndex; } else { // Search left int leftIndex = Math.min(midIndex - 1, midValue); int left = helper(start, leftIndex, inputs); if(left > 0) { return left; } // Search right int rightIndex = Math.max(midIndex + 1, midValue); return helper(rightIndex, end, inputs); } }