[Leetcode] Length of Last Word

Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string.

If the last word does not exist, return 0.

Note: A word is defined as a character sequence consists of non-space characters only.

For example, 
Given s = "Hello World",
return 5.

 

Solution:

关于java中的split函数：http://shukuiyan.iteye.com/blog/1058672

public class Solution {
    public int lengthOfLastWord(String s) {
       if(s==null||s.length()==0)
            return 0;
        String[] ss=s.split(" ");
        if(ss.length==0)
            return 0;
        return ss[ss.length-1].length();
    }
}

 

public class Solution {
    public int lengthOfLastWord(String s) {
       if(s==null||s.trim().length()==0)
            return 0;
        String[] ss=s.split(" ");
        return ss[ss.length-1].length();
    }
}