[bzoj2245]工作安排

由于价格是单调递增的,因此可以直接建立Si条边,流量和价格依次为给定的函数即可
(如果价格不递增,可以考虑动态加边等操作)

 1 #include<bits/stdc++.h>
 2 using namespace std;
 3 #define N 1005
 4 struct ji{
 5     int nex,to,len,cost;
 6 }edge[N*N];
 7 queue<int>q;
 8 int E,n,m,x,y,head[N],d[N],from[N],vis[N];
 9 long long ans;
10 void add(int x,int y,int z,int w){
11     edge[E].nex=head[x];
12     edge[E].to=y;
13     edge[E].len=z;
14     edge[E].cost=w;
15     head[x]=E++;
16     if (E&1)add(y,x,0,-w);
17 }
18 bool spfa(){
19     memset(d,0x3f,sizeof(d));
20     memset(vis,0,sizeof(vis));
21     q.push(0);
22     d[0]=0;
23     while (!q.empty()){
24         int k=q.front();
25         q.pop();
26         for(int i=head[k];i!=-1;i=edge[i].nex)
27             if ((edge[i].len)&&(d[edge[i].to]>d[k]+edge[i].cost)){
28                 d[edge[i].to]=d[k]+edge[i].cost;
29                 from[edge[i].to]=i;
30                 if (!vis[edge[i].to]){
31                     vis[edge[i].to]=1;
32                     q.push(edge[i].to);
33                 }
34             }
35         vis[k]=0;
36     }
37     return d[n+m+1]<0x3f3f3f3f;
38 }
39 int main(){
40     scanf("%d%d",&n,&m);
41     memset(head,-1,sizeof(head));
42     for(int i=1;i<=m;i++){
43         scanf("%d",&x);
44         add(i+n,n+m+1,x,0);
45     }
46     for(int i=1;i<=n;i++)
47         for(int j=1;j<=m;j++){
48             scanf("%d",&x);
49             if (x)add(i,j+n,0x3f3f3f3f,0);
50         }
51     for(int i=1;i<=n;i++){
52         scanf("%d",&x);
53         for(int j=1;j<=x;j++)scanf("%d",&d[j]);
54         d[x+1]=0x3f3f3f3f;
55         for(int j=0;j<=x;j++){
56             scanf("%d",&y);
57             add(0,i,d[j+1]-d[j],y);
58         }
59     }
60     while (spfa()){
61         x=0x3f3f3f3f;
62         for(int i=n+m+1;i;i=edge[from[i]^1].to)x=min(x,edge[from[i]].len);
63         ans+=1LL*x*d[n+m+1];
64         for(int i=n+m+1;i;i=edge[from[i]^1].to){
65             edge[from[i]].len-=x;
66             edge[from[i]^1].len+=x;
67         }
68     }
69     printf("%lld",ans);
70 }
View Code

 

posted @ 2019-11-16 16:47  PYWBKTDA  阅读(111)  评论(0编辑  收藏  举报