CF474F Ant colony(ST表+二分)

// Problem: CF474F Ant colony
// Contest: Luogu
// URL: https://www.luogu.com.cn/problem/CF474F
// Memory Limit: 250 MB
// Time Limit: 1000 ms
// 
// Powered by CP Editor (https://cpeditor.org)

#include<bits/stdc++.h>
using namespace std;
typedef long long ll;
typedef unsigned long long ull;
typedef pair<ll, ll>PLL;
typedef pair<int, int>PII;
typedef pair<double, double>PDD;
#define I_int ll
inline ll read()
{
    ll x = 0, f = 1;
    char ch = getchar();
    while(ch < '0' || ch > '9')
    {
        if(ch == '-')f = -1;
        ch = getchar();
    }
    while(ch >= '0' && ch <= '9')
    {
        x = x * 10 + ch - '0';
        ch = getchar();
    }
    return x * f;
}
  
inline void out(ll x){
    if (x < 0) x = ~x + 1, putchar('-');
    if (x > 9) out(x / 10);
    putchar(x % 10 + '0');
}
  
inline void write(ll x){
    if (x < 0) x = ~x + 1, putchar('-');
    if (x > 9) write(x / 10);
    putchar(x % 10 + '0');
}
  
#define read read()
#define closeSync ios::sync_with_stdio(0);cin.tie(0);cout.tie(0)
#define multiCase int T;cin>>T;for(int t=1;t<=T;t++)
#define rep(i,a,b) for(int i=(a);i<=(b);i++)
#define repp(i,a,b) for(int i=(a);i<(b);i++)
#define per(i,a,b) for(int i=(a);i>=(b);i--)
#define perr(i,a,b) for(int i=(a);i>(b);i--)
ll ksm(ll a, ll b,ll p)
{
    ll res = 1;
    while(b)
    {
        if(b & 1)res = res * a%p ;
        a = a * a %p;
        b >>= 1;
    }
    return res;
}

const int inf = 0x3f3f3f3f;
const int maxn=1e5+7,maxm=210000;

ll gcd(ll a,ll b){
	return b==0?a:gcd(b,a%b);
}

ll a[maxn],n,dp[maxn][32],b[maxn];
vector<int>g[maxn]; 
void init(){
	rep(j,1,n) dp[j][0]=a[j];
	for(int i=1;(1<<i)<=n;i++){
        for(int j=1;j+(1<<i)-1<=n;j++){
             dp[j][i]=gcd(dp[j][i-1],dp[j+(1<<(i-1))][i-1]);
        }
    }
}
ll query(int l,int r){
    int k=(int)log2((r-l+1));
    return gcd(dp[l][k],dp[r-(1<<k)+1][k]);
}
map<ll,ll>mp;

int main(){
	n=read;
	rep(i,1,n) a[i]=read,b[i]=a[i];
	sort(b+1,b+1+n);
	int m=unique(b+1,b+1+n)-(b+1);
	rep(i,1,n){
		int x=lower_bound(b+1,b+1+m,a[i])-b;
		mp[a[i]]=x;
		g[x].push_back(i);
	}
	init();
	int q=read;
	while(q--){
		int l=read,r=read;
		ll t=query(l,r);
		ll x=mp[t];
		ll ans=upper_bound(g[x].begin(),g[x].end(),r)-upper_bound(g[x].begin(),g[x].end(),l-1);
		cout<<r-l+1-ans<<"\n";
	}
	
	
	
	
	return 0;
}