树上背包DP Luogu P2014 选课

#include <cstdio>
#include <cctype>
#include <cstring>
#include <algorithm>
using namespace std;
const int MAXN = 305;
int n, m, fa[MAXN], val[MAXN], dp[MAXN][MAXN]; //表示i为根的子树中选j个的答案(不包含i)

inline void dfs(int u, int c)
{
    for(int v = 1; v <= n; v++) if(fa[v] == u)
    {
        for(int j = 0; j < c; j++) dp[v][j] = dp[u][j]; //继承其它儿子的答案
        dfs(v, c-1);
        for(int j = 1; j <= c; j++) dp[u][j] = max(dp[u][j], dp[v][j-1] + val[v]);
    }
}

int main()
{
    scanf("%d%d", &n, &m);
    for(int i = 1; i <= n; i++) scanf("%d%d", &fa[i], &val[i]);
    dfs(0, m);
    printf("%d\n", dp[0][m]);
}

 

posted @ 2019-12-14 14:52  _Ark  阅读(62)  评论(0编辑  收藏  举报