20171028机器学习之线性回归过拟合问题的解决方案

在函数中加入一个正则项:

 

三种方式:

一、Ridge回归(岭回归):

  优点:具有较高的准确性、鲁棒性以及稳定性

  缺点:求解速度慢

二、Lasso回归:

  优点:求解速度快(原理降维计算,把数据维度中存在的噪音和冗余去除)

  缺点:相比Ridge回归没有较高的准确性、鲁棒性以及稳定性

三、弹性网络:

  特点:综合了以上两种回归算法的特性。计算效率以及鲁棒性兼备。

 

 

几种回归解决拟合问题的综合比较:

GIthub:代码

https://github.com/chenjunhaolefa/AI/blob/master/MachineLearning/LinearRegression03.py

# coding=utf-8
'''
下面的代码是用一个小例子解决线性回归过拟合问题
'''
import numpy as np
import matplotlib as mpl
import matplotlib.pyplot as plt
import pandas as pd
import warnings
import sklearn
from sklearn.linear_model import LinearRegression, LassoCV, RidgeCV, ElasticNetCV
from sklearn.preprocessing import PolynomialFeatures
from sklearn.pipeline import Pipeline
from sklearn.linear_model.coordinate_descent import ConvergenceWarning

#解决画图产生的中文乱码问题
mpl.rcParams['font.sans-serif']=[u'simHei']
mpl.rcParams['axes.unicode_minus']=False

#生成一段数据来测试一下拟合问题
np.random.seed(100)
np.set_printoptions(linewidth=1000, suppress=True)
N = 10
x = np.linspace(0, 6, N) + np.random.randn(N)
y = 1.8*x**3 + x**2 - 14*x - 7 + np.random.randn(N)
x.shape = -1, 1
y.shape = -1, 1

#模型
models = [
    Pipeline([
            ('Poly', PolynomialFeatures()),
            ('Linear', LinearRegression(fit_intercept=False))
        ]),
    Pipeline([
            ('Poly', PolynomialFeatures()),
            ('Linear', RidgeCV(alphas=np.logspace(-3,2,50), fit_intercept=False))
        ]),
    Pipeline([
            ('Poly', PolynomialFeatures()),
            ('Linear', LassoCV(alphas=np.logspace(-3,2,50), fit_intercept=False))
        ]),
    Pipeline([
            ('Poly', PolynomialFeatures()),
            ('Linear', ElasticNetCV(alphas=np.logspace(-3,2,50), l1_ratio=[.1, .5, .7, .9, .95, 1], fit_intercept=False))
        ])
]

plt.figure(facecolor='W')
degree = np.arange (1, N, 2)  # 定义函数的阶数  X^2代表2阶函数 N表示N阶
dm = degree.size
colors = []  # 颜色
for c in np.linspace (16711680, 255, dm):
    colors.append ('#%06x' % c)
titles = [u'线性回归', u'Ridge回归', u'Lasso回归', u'ElasticNet']

for t in range(4):
    model = models[t]
    plt.subplot(2, 2, t + 1)
    plt.plot(x, y, 'ro', ms=5, zorder=N)

    for i, d in enumerate(degree):
        model.set_params(Poly__degree=d)

        model.fit(x, y.ravel())

        lin = model.get_params('Linear')['Linear']

        output = u'%s:%d阶,系数为:' % (titles[t], d)
        print output, lin.coef_.ravel()

        x_hat = np.linspace(x.min(), x.max(), num=100)
        x_hat.shape = -1, 1

        y_hat = model.predict(x_hat)

        s = model.score(x, y)

        z = N - 1 if (d == 2) else 0
        label = u'%d阶, 正确率=%.3f' % (d, s)
        plt.plot(x_hat, y_hat, color=colors[i], lw=2, alpha=0.75, label=label, zorder=z)

    plt.legend(loc='upper left')
    plt.grid(True)
    plt.title(titles[t])
    plt.xlabel('X', fontsize=16)
    plt.ylabel('Y', fontsize=16)

plt.tight_layout(1, rect=(0, 0, 1, 0.95))
plt.suptitle(u'各种不同线性回归过拟合显示', fontsize=22)
plt.show()

  

 

posted @ 2017-10-29 09:03  Ootori  阅读(2465)  评论(0编辑  收藏  举报