iOS获取窗口当前显示的控制器
解决类似网易新闻客户端收到新闻推送后,弹出一个UIAlert,然后跳转到新闻详情页面这种需求
1.提供一个UIView的分类方法,这个方法通过响应者链条获取view所在的控制器
- (UIViewController *)parentController { UIResponder *responder = [self nextResponder]; while (responder) { if ([responder isKindOfClass:[UIViewController class]]) { return (UIViewController *)responder; } responder = [responder nextResponder]; } return nil; }
2.通过控制器的布局视图可以获取到控制器实例对象
modal的展现方式需要取到控制器的根视图
+ (UIViewController *)currentViewController { UIWindow *keyWindow = [UIapplication sharedApplication].keyWindow; // modal展现方式的底层视图不同 // 取到第一层时,取到的是UITransitionView,通过这个view拿不到控制器 UIView *firstView = [keyWindow.subviews firstObject]; UIView *secondView = [firstView.subviews firstObject]; UIViewController *vc = secondView.parentController; if ([vc isKindOfClass:[UITabBarController class]]) { UITabBarController *tab = (UITabBarController *)vc; if ([tab.selectedViewController isKindOfClass:[UINavigationController class]]) { UINavigationController *nav = (UINavigationController *)tab.selectedViewController; return [nav.viewControllers lastObject]; } else { return tab.selectedViewController; } } else if ([vc isKindOfClass:[UINavigationController class]]) { UINavigationController *nav = (UINavigationController *)vc; return [nav.viewControllers lastObject]; } else { return vc; } return nil; }
相关链接:获取窗口当前显示的控制器