BUUCTF-RE-findit

一、

apk文件用jeb打开   反编译

二、jeb分析

package com.example.findit;

import android.os.Bundle;
import android.support.v7.app.ActionBarActivity;
import android.view.MenuItem;
import android.view.View$OnClickListener;
import android.view.View;

public class MainActivity extends ActionBarActivity {
    public MainActivity() {
        super();
    }

    protected void onCreate(Bundle arg8) {
        super.onCreate(arg8);
        this.setContentView(2130903064);
        this.findViewById(2131034173).setOnClickListener(new View$OnClickListener(new char[]{'T', 'h', 'i', 's', 'I', 's', 'T', 'h', 'e', 'F', 'l', 'a', 'g', 'H', 'o', 'm', 'e'}, this.findViewById(2131034174), new char[]{'p', 'v', 'k', 'q', '{', 'm', '1', '6', '4', '6', '7', '5', '2', '6', '2', '0', '3', '3', 'l', '4', 'm', '4', '9', 'l', 'n', 'p', '7', 'p', '9', 'm', 'n', 'k', '2', '8', 'k', '7', '5', '}'}, this.findViewById(2131034175)) {
            public void onClick(View arg13) {
                int v11 = 17;
                int v10 = 122;
                int v9 = 90;
                int v8 = 65;
                int v7 = 97;
                char[] v3 = new char[v11];
                char[] v4 = new char[38];
                int v0;
                for(v0 = 0; v0 < v11; ++v0) {
                    if(this.val$a[v0] >= 73 || this.val$a[v0] < v8) {
                        if(this.val$a[v0] < 105 && this.val$a[v0] >= v7) {
                        label_39:
                            v3[v0] = ((char)(this.val$a[v0] + 18));
                            goto label_44;
                        }

                        if(this.val$a[v0] >= v8 && this.val$a[v0] <= v9 || this.val$a[v0] >= v7 && this.val$a[v0] <= v10) {
                            v3[v0] = ((char)(this.val$a[v0] - 8));
                            goto label_44;
                        }

                        v3[v0] = this.val$a[v0];
                    }
                    else {
                        goto label_39;
                    }

                label_44:
                }

                if(String.valueOf(v3).equals(this.val$edit.getText().toString())) {
                    v0 = 0;
                    goto label_18;
                }
                else {
                    this.val$text.setText("答案错了肿么办。。。不给你又不好意思。。。哎呀好纠结啊~~~");
                    return;
                label_18:
                    while(v0 < 38) {
                        if(this.val$b[v0] < v8 || this.val$b[v0] > v9) {
                            if(this.val$b[v0] >= v7 && this.val$b[v0] <= v10) {
                            label_80:
                                v4[v0] = ((char)(this.val$b[v0] + 16));
                                if((v4[v0] <= v9 || v4[v0] >= v7) && v4[v0] < v10) {
                                    goto label_95;
                                }

                                v4[v0] = ((char)(v4[v0] - 26));
                                goto label_95;
                            }

                            v4[v0] = this.val$b[v0];
                        }
                        else {
                            goto label_80;
                        }

                    label_95:
                        ++v0;
                    }

                    this.val$text.setText(String.valueOf(v4));
                }
            }
        });
    }

    public boolean onOptionsItemSelected(MenuItem arg3) {
        boolean v1 = arg3.getItemId() == 2131034176 ? true : super.onOptionsItemSelected(arg3);
        return v1;
    }
}

发现第17行的疑似加密过后的flag字符串pvkq{m164675262033l4m49lnp7p9mnk28k75}

应该是用了移位  移位密码最著名的就是凯撒密码

脚本如下

a=input()
model = "abcdefghijklmnopqrstuvwxyz"
flag=''
for i in range(1,27):
    print("key=%d"%i, end='\n')
    for s in a:
        if s.isalpha():              //isalpha()测字符串是否只由字母组成
            n = model.find(s)        //find()检测字符串中是否包含子字符串model
            s = model[n-i]
        print(s, end='')
    print('\n')

 

三、flag

flag{c164675262033b4c49bdf7f9cda28a75}