Codeforces 115 div1 B.Mushroom Scientists

链接

一开始其实有想到按abc的比例去分xyz
但是觉得算了
数学这么差没什么自信

事实上确实是这样

新学了琴生不等式和AMGM不等式用来证明这个

这里最好多输出几位小数，防止加起来因为四舍五入的原因超过S

#include <iostream>
#include <iomanip>
#include <cstdio>
using namespace std;
 
int main() {
 
    int S,a,b,c; cin >> S >> a >> b >> c;
    double x = 0,y = 0,z = 0;
 
    if(a+b+c==0) {
        x = y = z = S/3;
        cout << S << " " << 0 << " " << 0;
        return 0;
    }
    x = (double)(S*a)/(a+b+c);
    y = (double)(S*b)/(a+b+c);
    z = (double)(S*c)/(a+b+c);
 
 
    printf("%.18lf %.18lf %.18lf",x,y,z);
    return 0;
}