[考试总结]noip模拟46

脑袋确实是不好使了需要回家暴颓治疗

数数数树鼠树

真好玩。

数数

大水题一个,妥妥的签到题目,然后。。。

我没签上

asdadasdad.png

气展了!!!

其实我还是想麻烦了。

就是我们实际上就是排序之后每一次找头上和尾巴上的就行

#include<bits/stdc++.h>
using std::cout; using std::endl;
#define try(i,a,b) for(register signed i=a;i<=b;++i)
#define throw(i,a,b) for(register signed i=a;i>=b;--i)
#define asm(i,x) for(register signed i=head[x];i;i=edge[i].next)
namespace xin_io
{
	#define sb(x) cout<<#x" = "<<x<<' '
	#define jb(x) cout<<#x" = "<<x<<endl
	#define debug cout<<"debug"<<endl
	#define gc() p1 == p2 and (p2 = (p1 = buf) + fread(buf,1,1<<20,stdin),p1 == p2) ? EOF : *p1++
	char buf[1<<20],*p1 = buf,*p2 = buf; int ak; typedef long long ll; typedef unsigned long long ull;
	class xin_stream{public:template<typename type>inline xin_stream &operator >> (type &s)
	{
		register int f = 0;s = 0; register char ch = gc();
		while(!isdigit(ch)) {f |= ch == '-'; ch = gc();}
		while( isdigit(ch)) s = (s << 1) + (s << 3) + (ch  xor 48),ch = gc(); return s = f ? -s : s,*this;
	}}io;
}
using namespace xin_io; static const int maxn = 1e6+10,inf = 1e9+7; const ll llinf = 1e18+7;
#define int long long
namespace xin
{
	int a[maxn],n;
	int ans = 0,sum = 0,zhi1  = 0,zhi2 = 0;
	inline short main()
	{
		io >> n;
		try(i,1,n) io >> a[i];
		std::sort(a+1,a+n+1);
		zhi1 = 1; zhi2 = n;
		try(i,1,n)
		{
			if(i & 1)
			{
				ans += sum;
			}
			else
			{
				sum += a[zhi2] - a[zhi1];
				zhi2 --; zhi1 ++;
				ans += sum;
			}
			cout<<ans<<endl;
		}
		return 0;
	}
}
signed main() {return xin::main();}

数树

不会,鸽了。

鼠树

似乎我是没脸暴力水过去的。。。。

首先使用一个朴实无华的laji区间加减线段树。

然后我们还要有一个 \(vector\) 来记录每个黑色的点的管辖。

然后每个操作就是:

  1. 直接调用 \(query(1,1,n,id[x],id[x])\)
  2. \(x\) 的子树加上 \(val\) ,然后要把剩下的 \(vector\) 当中的东西的子树都减掉 \(val\)
  3. 直接 \(query(1,1,n,id[x],id[x]+siz[x]-1)\)
  4. 就是反复进行 \(2\)
  5. 这个变化之后要进行\(vector\)记录
  6. 大致与 \(5\) 相同
#include<bits/stdc++.h>
using std::endl; using std::cout;
#define try(i,a,b) for(register signed i=a;i<=b;++i)
#define throw(i,a,b) for(register signed i=a;i>=b;--i)
#define asm(i,x) for(register signed i=head[x];i;i=edge[i].next)
namespace xin_io
{
	#define debug cout<<"debug"<<endl
	#define sb(x) cout<<#x" = "<<x<<' '
	#define jb(x) cout<<#x" = "<<x<<endl
	#define gc() p1 == p2 and (p2 = (p1 = buf) + fread(buf,1,1<<20,stdin),p1 == p2) ? EOF : *p1 ++
	char buf[1<<20],*p1 = buf,*p2 = buf; typedef long long ll; typedef unsigned long long ull;
	class xin_stream{public:template<typename type>xin_stream &operator >> (type &s)
	{
		register bool f = 0; s = 0; register char ch = gc();
		while(!isdigit(ch)) f |= ch == '-',ch = gc();
		while( isdigit(ch)) s = (s << 1) + (s << 3) + (ch xor 48),ch = gc(); return s = f ? -s : s,*this;
	}}io;
}
using namespace xin_io; static const int maxn = 5e6+10;
namespace xin
{
	int n,m;
	int fa[maxn];
	class xin_edge{public:int next,ver;}edge[maxn];
	int head[maxn],rp = 0;
	inline void add(int x,int y) {edge[++rp].ver = y ;edge[rp].next = head[x]; head[x] = rp;}
	int col[maxn],dep[maxn],siz[maxn],id[maxn],tot;
	std::vector<int>cashe[maxn];
	void dfs(int x)
	{
		siz[x] = 1; dep[x] = dep[fa[x]] + 1; id[x] = ++tot;
		asm(i,x)
		{
			register int y = edge[i].ver;
			if(y == fa[x]) continue;
			dfs(y);
			siz[x] += siz[y];
		}
	}
	class xin_seg
	{
		private:
			#define ls(fa) (fa << 1)
			#define rs(fa) (fa << 1 | 1)
			inline void up(int fa) {t[fa].s = t[ls(fa)].s + t[rs(fa)].s;}
			inline void down(int fa,int l,int r)
			{
				if(!t[fa].debt) return ;
				register int mid = l + r >> 1;
				(t[ls(fa)].s += (mid - l + 1) * t[fa].debt); (t[rs(fa)].s += (r - mid) * t[fa].debt);
				(t[ls(fa)].debt += t[fa].debt); (t[rs(fa)].debt += t[fa].debt);
				t[fa].debt = 0;
			}
		public:
			class xin_tree{public:unsigned s,debt;}t[maxn];
			void update(int fa,int l,int r,int ql,int qr,int val)
			{
				if(ql <= l and qr >= r) return (t[fa].s += (r - l + 1) * val),(t[fa].debt += val),void();
				register int mid = l + r >> 1;
				down(fa,l,r);
				if(ql <= mid) update(ls(fa),l,mid,ql,qr,val); if(qr > mid) update(rs(fa),mid+1,r,ql,qr,val);
				up(fa);
			}
			unsigned query(int fa,int l,int r,int ql,int qr)
			{
				if(ql <= l and qr >= r) return t[fa].s;
				register int mid = l + r >> 1;unsigned ret = 0;
				down(fa,l,r);
				if(ql <= mid) (ret += query(ls(fa),l,mid,ql,qr)); if(qr > mid) (ret += query(rs(fa),mid+1,r,ql,qr));
				return ret;
			}
	}t;
	int up[maxn];
	inline short main()
	{
		io >> n >> m;
		try(i,2,n) 
		{
			io >> fa[i];
			add(fa[i],i);
		}
		col[1] = 1; dfs(1);
		try(cse,1,m)
		{
			register int op,k; io >> op >> k;
			if(op == 1)
				printf("%u\n",t.query(1,1,n,id[k],id[k]));
			else if(op == 2)
			{
				register int val; io >> val;
				t.update(1,1,n,id[k],id[k] + siz[k] - 1,val);
				for(auto v : cashe[k]) t.update(1,1,n,id[v],id[v] + siz[v] - 1,-val);
			}
			else if(op == 3)
				printf("%u\n",t.query(1,1,n,id[k],id[k] + siz[k] - 1));
			else if(op == 4)
			{
				register int val; io >> val;
				if(col[k] == 1)
				{
					t.update(1,1,n,id[k],id[k] + siz[k] - 1,val);
					continue;
				}
				register int now = k;
				while(!col[now]) now = fa[now];
				for(auto v : cashe[now])
					if(id[v] >= id[k] and id[v] <= id[k] + siz[k] - 1)
						t.update(1,1,n,id[v],id[v] + siz[v] - 1,val);
			}
			else if(op == 5)
			{
				register int now = k;
				while(!col[now]) now = fa[now];
				up[k] = now;
				int len = cashe[now].size() - 1;
				try(i,0,len)
				{
					register int v = cashe[now][i];

					if(id[v] >= id[k] and id[v] <= id[k] + siz[k] - 1)
					{
						cashe[k].push_back(v); up[v] = k;
						cashe[now][i] = cashe[now][len];
						i --; len --;
						cashe[now].pop_back();
					}
				}
				cashe[now].push_back(k);
				col[k] = 1;
			}
			else
			{
				for(auto v : cashe[k])
				{
					cashe[up[k]].push_back(v);
					up[v] = up[k];
				}
				cashe[k].clear();
				int len = (int)cashe[up[k]].size() - 1;
				try(i,0,len)
					if(cashe[up[k]][i] == k)
					{
						cashe[up[k]][i] = cashe[up[k]][len];
						cashe[up[k]].pop_back();
						break;
					}
				up[k] = col[k] = 0;
			}
		}
		return 0;
	}
}
signed main() {return xin::main();}

ckw的树

俺不会,又鸽le.....

posted @ 2021-08-25 08:19  NP2Z  阅读(38)  评论(0编辑  收藏  举报