ZOJ Problem Set - 1007 - Numerical Summation of a Series

 

public class Main {
    public static void main(String[] args) {
        double x = 0.000;
        double sum, k;
        for(int i = 1; i <= 2001; i++) {
            sum = 0.000;
            for(k = 1; k < 10000; k++) {
                sum += 1.0/(k*(k+1)*(k+x));
            }
            sum = (1.0-x)*(sum + 1.0/(20000 * 10000)) + 1.0;
            System.out.printf("%5.3f %16.12f\n", x, sum);
            x += 0.001;
        }
    }
}

 

posted on 2018-02-04 22:05  NEU-2015  阅读(133)  评论(0编辑  收藏  举报

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