BZOJ2213 [Poi2011]Difference 【乱搞】

题目链接

BZOJ2213

题解

考虑任意一对点的贡献，单独拿出那些点所在位置
一个设为\(1\)，一个设为\(-1\)，从头到尾扫一遍维护前缀和，以及当前最小前缀和
两者相减更新答案
需要注意的是当前最小前缀和更新的位置之后必须存在另一个字符，否则就不满足最小出现次数最少大于\(0\)的限制

由于每个位置最多拿出来\(26\)次，所以是\(O(26n)\)的

#include<algorithm>
#include<iostream>
#include<cstring>
#include<cstdio>
#include<cctype>
#include<cmath>
#include<vector>
#include<map>
#define Redge(u) for (int k = h[u],to; k; k = ed[k].nxt)
#define REP(i,n) for (int i = 1; i <= (n); i++)
#define mp(a,b) make_pair<int,int>(a,b)
#define cls(s) memset(s,0,sizeof(s))
#define cp pair<int,int>
#define LL long long int
using namespace std;
const int maxn = 1000005,maxm = 100005,INF = 1000000000;
inline int read(){
	int out = 0,flag = 1; char c = getchar();
	while (c < 48 || c > 57){if (c == '-') flag = -1; c = getchar();}
	while (c >= 48 && c <= 57){out = (out << 3) + (out << 1) + c - 48; c = getchar();}
	return out * flag;
}
vector<int> pos[26];
int n,ans;
void work(int x,int y){
	int nowx = 0,nowy = 0,minx = INF,miny = INF,mnx = 0,mny = 0;
	unsigned int px = 0,py = 0;
	while (px < pos[x].size() || py < pos[y].size()){
		if (py == pos[y].size() || (px < pos[x].size() && pos[x][px] < pos[y][py])){
			miny = min(miny,mny);
			nowx++; nowy--;
			px++;
		}
		else {
			minx = min(minx,mnx);
			nowy++; nowx--;
			py++;
		}
		mnx = min(nowx,mnx); mny = min(mny,nowy);
		if (minx < INF) ans = max(ans,nowx - minx);
		if (miny < INF) ans = max(ans,nowy - miny);
	}
}
int main(){
	n = read(); int x; char c = getchar();
	while (!isalpha(c)) c = getchar();
	for (int i = 1; i <= n; i++){
		x = c - 'a';
		pos[x].push_back(i);
		c = getchar();
	}
	for (int x = 0; x < 26; x++)
		for (int y = x + 1; y < 26; y++)
			work(x,y);
	printf("%d\n",ans);
	return 0;
}