[洛谷P1580]yyy loves Easter_Egg I

题目大意:很多人@一个人,如果那个人忍不住说话了,就轰炸成功,如果那个人没说话或者别的人没有@他或@很多个人,则轰炸失败。(具体见原题)

解题思路:字符串处理,好好用sscanf即可(细节见代码)。

C++ Code:

#include<cstring>
#include<algorithm>
#include<cstdio>
char s[1050],zha[1050],shuohua[1050],At[1050];
int q=1;
int main(){
	fgets(s,1005,stdin);
	sscanf(strstr(s,"@"),"@yyy loves %s",zha);
	while(1){
		fgets(s,1005,stdin);
		if(strlen(s)<5)break;//读入结束
		++q;
		sscanf(s,"yyy loves %s",shuohua);
		if(strcmp(zha,shuohua)==0){//油炸成功 
			printf("Successful @yyy loves %s attempt\n",zha);
			return 0;
		}
		if(std::count(s,s+strlen(s),'@')!=1){//队形被破坏,油炸失败
			printf("Unsuccessful @yyy loves %s attempt\n%d\nyyy loves %s\n",zha,q,shuohua);
			return 0;
		}else{
			sscanf(strstr(s,"@"),"@yyy loves %s",At);
			if(strcmp(At,zha)){//队形被破坏,油炸失败
				printf("Unsuccessful @yyy loves %s attempt\n%d\nyyy loves %s\n",zha,q,shuohua);
				return 0;
			}
		}
	}
	//队形没有被打破
	printf("Unsuccessful @yyy loves %s attempt\n%d\nGood Queue Shape\n",zha,q);
	return 0;
}

 

posted @ 2017-07-28 09:02  Mrsrz  阅读(275)  评论(0编辑  收藏  举报