13、集合--HashSet相关方法源码解析(等map更新完成之后在进行补充)
相关使用的实例地址:https://www.cnblogs.com/Mrchengs/p/10850333.html
HashMap的基本解析:https://www.cnblogs.com/Mrchengs/p/10852667.html
1、HashSet set = new HashSet();
public HashSet() { map = new HashMap<>(); }
static final long serialVersionUID = -5024744406713321676L; private transient HashMap<E,Object> map; private static final Object PRESENT = new Object();
此时可以看出HashSet时基于HashMap实现的
HashMap的实现在之后的博文中将进行更新
此时仅需要知道底层的实现时HashMap
首先定义一个长度16的数组
2、add(E e):添加方法
public boolean add(E e) { return map.put(e, PRESENT)==null; }
private static final Object PRESENT = new Object();
HashMap.java
public V put(K key, V value) { return putVal(hash(key), key, value, false, true); }
final V putVal(int hash, K key, V value, boolean onlyIfAbsent, boolean evict) { Node<K,V>[] tab; Node<K,V> p; int n, i; if ((tab = table) == null || (n = tab.length) == 0) n = (tab = resize()).length; if ((p = tab[i = (n - 1) & hash]) == null) tab[i] = newNode(hash, key, value, null); else { Node<K,V> e; K k; if (p.hash == hash && ((k = p.key) == key || (key != null && key.equals(k)))) e = p; else if (p instanceof TreeNode) e = ((TreeNode<K,V>)p).putTreeVal(this, tab, hash, key, value); else { for (int binCount = 0; ; ++binCount) { if ((e = p.next) == null) { p.next = newNode(hash, key, value, null); if (binCount >= TREEIFY_THRESHOLD - 1) // -1 for 1st treeifyBin(tab, hash); break; } if (e.hash == hash && ((k = e.key) == key || (key != null && key.equals(k)))) break; p = e; } } if (e != null) { // existing mapping for key V oldValue = e.value; if (!onlyIfAbsent || oldValue == null) e.value = value; afterNodeAccess(e); return oldValue; } } ++modCount; if (++size > threshold) resize(); afterNodeInsertion(evict); return null; }
HashMap的基本解析:https://www.cnblogs.com/Mrchengs/p/10852667.html
3、size()方法求长度
public int size() { return map.size(); }
HashMap.java
transient int size;
public int size() { return size; }
HashMap的基本解析:https://www.cnblogs.com/Mrchengs/p/10852667.html
4、contains(Object o):
public boolean contains(Object o) { return map.containsKey(o); }
HashMap.java
public boolean containsKey(Object key) { return getNode(hash(key), key) != null; }
final Node<K,V> getNode(int hash, Object key) { Node<K,V>[] tab; Node<K,V> first, e; int n; K k; if ((tab = table) != null && (n = tab.length) > 0 && (first = tab[(n - 1) & hash]) != null) { if (first.hash == hash && // always check first node ((k = first.key) == key || (key != null && key.equals(k)))) return first; if ((e = first.next) != null) { if (first instanceof TreeNode) return ((TreeNode<K,V>)first).getTreeNode(hash, key); do { if (e.hash == hash && ((k = e.key) == key || (key != null && key.equals(k)))) return e; } while ((e = e.next) != null); } } return null; }
HashMap的基本解析:https://www.cnblogs.com/Mrchengs/p/10852667.html
5、retainAll(Collection c):删除c中没有的元素
AbstractCollection.java
public boolean retainAll(Collection<?> c) { Objects.requireNonNull(c); boolean modified = false; Iterator<E> it = iterator(); while (it.hasNext()) { if (!c.contains(it.next())) { it.remove(); modified = true; } } return modified; }
6、remove(Object o):移除指定元素
public boolean remove(Object o) { return map.remove(o)==PRESENT; }
private static final Object PRESENT = new Object();
HashMap.java
public V remove(Object key) { Node<K,V> e; return (e = removeNode(hash(key), key, null, false, true)) == null ? null : e.value; }
final Node<K,V> removeNode(int hash, Object key, Object value, boolean matchValue, boolean movable) { Node<K,V>[] tab; Node<K,V> p; int n, index; if ((tab = table) != null && (n = tab.length) > 0 && (p = tab[index = (n - 1) & hash]) != null) { Node<K,V> node = null, e; K k; V v; if (p.hash == hash && ((k = p.key) == key || (key != null && key.equals(k)))) node = p; else if ((e = p.next) != null) { if (p instanceof TreeNode) node = ((TreeNode<K,V>)p).getTreeNode(hash, key); else { do { if (e.hash == hash && ((k = e.key) == key || (key != null && key.equals(k)))) { node = e; break; } p = e; } while ((e = e.next) != null); } } if (node != null && (!matchValue || (v = node.value) == value || (value != null && value.equals(v)))) { if (node instanceof TreeNode) ((TreeNode<K,V>)node).removeTreeNode(this, tab, movable); else if (node == p) tab[index] = node.next; else p.next = node.next; ++modCount; --size; afterNodeRemoval(node); return node; } } return null; }
HashMap的基本解析:https://www.cnblogs.com/Mrchengs/p/10852667.html
7、Clear()方法
public void clear() { map.clear(); }
HashMap.java
public void clear() { Node<K,V>[] tab; modCount++; if ((tab = table) != null && size > 0) { size = 0; for (int i = 0; i < tab.length; ++i) tab[i] = null; } }
HashMap的基本解析:https://www.cnblogs.com/Mrchengs/p/10852667.html