python xml操作

1) 导入import xml.etree.ElementTree as ET

2）需要一个xml文件(sensorexpert_brand.xml)，结构如下所示：

<?xml version="1.0" encoding="UTF-8"?>
<response>
    <error>0</error>
    <msg>success</msg>
    <data>
        <total>10602</total>
        <pageSize>100</pageSize>
        <rows>
            <item>
                <id>11683</id>
                <full_name>Zywyn</full_name>
                <flag></flag>
                <country_name></country_name>
                <product_total>0</product_total>
                <brand_type>制造商</brand_type>
                <link>/brand/11683.html</link>
            </item>
            <item>
                <id>6005</id>
                <full_name>阿尔法电线</full_name>
                <flag></flag>
                <country_name></country_name>
                <product_total>1</product_total>
                <brand_type></brand_type>
                <link>/brand/6005.html</link>
            </item>
        </rows>
    </data>
</response>

3) 读取相关代码

    def parse(self, response):
        filename='ebs_crawler/files/sensorexpert_brand.xml'
        with open(filename,'w',encoding='UTF-8-sig') as file_object:
            file_object.write(response.text) 
            self.logger.info(f"覆盖xml文件成功:{response.request.url}")

        tree = ET.parse(filename) 
        root = tree.getroot()
        links=[]
        for chlid in root[2][2]:
            links.append('https://www.sensorexpert.com.cn'+chlid[6].text)
        self.save(links)

　　注意，ET.parse 方法中参数，只支持文件地址，不支持文件内容。