ZOJ4106 Lucky 7 in the Pocket

给出一个数n 要你求出一个大于等于n且能被7整除但不能被4整除的数

水题

AC代码：

#include<bits/stdc++.h>
#define pi acos(-1)
typedef long long ll;
typedef unsigned long long ull;
using namespace std;

namespace io {
    const int SIZE = 1e7 + 10;
    char inbuff[SIZE];
    char *l, *r;
    inline void init() {
        l = inbuff;
        r = inbuff + fread(inbuff, 1, SIZE, stdin);
    }
    inline char gc() {
        if (l == r) init();
        return (l != r) ? *(l++) : EOF;
    }
    void read(int &x) {
        x = 0; char ch = gc();
        while(!isdigit(ch)) ch = gc();
        while(isdigit(ch)) x = x * 10 + ch - '0', ch = gc();
    }
} using io::read;

bool cmp(const int &a, const int &b){
    return a > b;
}

int main(){
    ios::sync_with_stdio(false);
    int t;
    cin>>t;
    int n;
    while (t--){
        cin>>n;
        int m;
        if (!(n % 7)){
            if (n % 4) cout<<n<<endl;
            else cout<<n + 7<<endl;
        }
        else{
            n = (n / 7 + 1) * 7;
            while (!(n % 4)){
                n += 7;
            }
            cout<<n<<endl;
        }
    }
    return 0;
}