//MiYu原创, 转帖请注明 : 转载自 ______________白白の屋
题目地址 :
http://acm.hdu.edu.cn/showproblem.php?pid=1106
很简单的一道水题, 就是直接字符串拆分就行了
代码:
题目地址 :
http://acm.hdu.edu.cn/showproblem.php?pid=1106
很简单的一道水题, 就是直接字符串拆分就行了
代码:
//MiYu原创, 转帖请注明 : 转载自 ______________白白の屋
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
int cmp ( const void *p, const void *t )
{
return *(int *)p - *(int *)t;
}
char s[1010];
int a[1010];
int main()
{
while ( scanf("%s",s) != EOF )
{
char *t;
int n = 1;
memset ( a, 0, sizeof ( a ) );
t = strtok ( s,"5" );
a[0] = atoi ( t );
while ( t = strtok ( NULL,"5" ) )
{
a[ n ++ ] = atoi ( t );
}
qsort ( a, n, sizeof ( int ), cmp );
for ( int i = 0; i != n; ++ i )
{
printf(i ? " %d" : "%d",a[i]);
}
putchar ( '\n' );
}
return 0;
}
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