C++Primer第五版——习题答案详解(八)


习题答案目录:https://www.cnblogs.com/Mered1th/p/10485695.html

第9章 顺序容器


练习9.1
a.list,需要按字典序插入,可能插入位置在中间
b.deque,需要在头部和尾部操作
c.vector

练习9.2

list<deque<int>> li;

练习9.4

bool findInt(vector<int> &vec, int x) {
	for (auto i : vec) {
		if (i == x) {
			return true;
		}
	}
	return false;
}

练习9.5

int findInt(vector<int> &vec, int x) {
	for (auto i : vec) {
		if (i == x) {
			return x;
		}
	}
	return -1;
}

练习9.6
改成 iter1!=iter2

练习9.7

vector<int>::size_type;

练习9.8

list<string>::const_iterator;
list<string>::iterator;

练习9.9
begin返回容器的iterator类型
cbegin返回容器的const_iterator类型

练习9.10

#include<string>
#include<vector>
#include<list>
#include<iostream>

using namespace std;

int main() {
	list<int> li(5, 3);
	vector<int> ivec(5, 5);

	vector<double> dvec(li.begin(), li.end());
	for (auto i : dvec) {
		cout << i << " ";
	}
	cout << endl;

	vector<double> dvec2(ivec.begin(), ivec.end());
	for (auto i : dvec2) {
		cout << i << " ";
	}
	cout << endl;

	system("pause");
	return 0;
}

练习9.14

list<const char *> oldli = { "a","an","the" };
        vector<string> svec;
        svec.assign(oldli.begin(), oldli.end());

练习9.15

bool isEquel(vector<int> &a, vector<int> &b) {
	if (a == b) return true;
	else return false;
}

练习9.16

bool isEquel(vector<int> &a, list<int> &b) {
	vector<int> c(b.begin(), b.end());
	if (a == c) return true;
	else return false;
}

练习9.18

#include<iostream>
#include<string>
#include<deque>

using namespace std;

int main() {
	string s;
	deque<string> ans;
	while (cin >> s) {
		ans.push_back(s);
	}
	for (auto it = ans.begin();it != ans.end();++it) {
		cout << *it << endl;
	}
	system("pause");
	return 0;
}

练习9.19
将deque改为list即可。

#include<iostream>
#include<string>
#include<deque>
#include<list>

using namespace std;

int main() {
	string s;
	list<string> ans;
	while (cin >> s) {
		ans.push_back(s);
	}
	for (auto it = ans.begin();it != ans.end();++it) {
		cout << *it << endl;
	}
	system("pause");
	return 0;
}

练习9.20

#include<iostream>
#include<deque>
#include<list>

using namespace std;

int main() {
	list<int> ori = { 1,2,3,4,5,6 };
	deque<int> odd, even;
	for (auto i : ori) {
		if (i % 2) {
			even.push_back(i);
		}
		else {
			odd.push_back(i);
		}
	}
	for (auto i : odd) {
		cout << i << " ";
	}
	cout << endl;
	for (auto i : even) {
		cout << i << " ";
	}

	system("pause");
	return 0;
}

练习9.22

#include<iostream>
#include<string>
#include<vector>

using namespace std;

void func(vector<int> &iv, int some_val) {
	int extra = 0;
	vector<int>::iterator iter = iv.begin();
	while (iter != (iv.begin() + iv.size() / 2 + extra)) {
		if (*iter == some_val) {
			iter = iv.insert(iter, 2 * some_val);
			++extra;
			++iter;
		}
		++iter;
	}
}
int main() {
	vector<int> iv = { 1,2,3,4 };
	func(iv, 2);
	for (auto i : iv) {
		cout << i << " ";
	}
	system("pause");
	return 0;
}

练习9.24

#include<iostream>
#include<vector>

using namespace std;

int main() {
	vector<int> vec;
	int a = vec.at(0),
		b = vec[0],
		c = vec.front();
	auto d = vec.begin();
	cout << "a: " << a << endl;
	cout << "b: " << b << endl;
	cout << "c: " << c << endl;
	cout << "d: " << *d << endl;
	system("pause");
	return 0;
}

练习9.25
如果elem1与elem2相等,则一个元素都不会删除。
如果elem2是尾后迭代器,则会从elem1元素删除到最后一个元素。
如果elem1与elem2都是尾后迭代器,则一个元素都不会删除。

练习9.26

#include<vector>
#include<iostream>
#include<list>
using namespace std;

int main() {
	int ia[] = { 0,1,1,2,3,5,8,13,21,55,89 };
	vector<int> vec(ia, end(ia));
	list<int> li(ia, end(ia));
	for (auto it = li.begin(); it != li.end();) {
		if (*it % 2 == 1) {
			it = li.erase(it);
		}
		else {
			++it;
		}
	}
	for (auto i : li) {
		cout << i << " ";
	}
	cout << endl;
	for (auto it = vec.begin();it != vec.end();) {
		if (*it % 2 == 0) {
			it = vec.erase(it);
		}
		else {
			++it;
		}
	}
	for (auto i : vec) {
		cout << i << " ";
	}
	cout << endl;
	system("pause");
	return 0;
}

练习9.27

#include<iostream>
#include<forward_list>

using namespace std;

int main() {
	forward_list<int> flst = { 0,1,2,3,4,5,6,7,8,9 };
	auto prev = flst.before_begin();
	auto curr = flst.begin();
	while (curr != flst.end()) {
		if (*curr % 2) {
			curr = flst.erase_after(prev);
		}
		else {
			prev = curr;
			++curr;
		}
	}
	for (auto i : flst) {
		cout << i << " ";
	}
	system("pause");
	return 0;
}

练习9.28

#include<forward_list>
#include<iostream>
#include<string>

using namespace std;

void func(forward_list<string> &flst, string a, string b) {
	auto it = flst.begin();
	auto prev = flst.before_begin();
	bool flag = false;
	while (it != flst.end()) {
		if (*it == a) {
			it = flst.insert_after(it, b);
			flag = true;
			break;
		}
		else {
			prev = it;
			++it;
		}
	}
	if (!flag) flst.insert_after(prev, b);
}

int main() {
	forward_list<string> flst = { "abc","bcd","eee" };
	string a = "aaa", b = "fff";
	func(flst, a, b);
	for (auto i : flst) {
		cout << i << " ";
	}
	cout << endl;
	system("pause");
	return 0;
}

练习9.29
vec.resize(100)会将90个值为0的元素添加到末尾。
vec.resize(10)会将末尾90个元素删去。

练习9.30
元素类型必须提供一个默认的构造函数。

练习9.31
list

#include<iostream>
#include<vector>
#include<list>
using namespace std;

int main() {
	list<int> lst = { 0,1,2,3,4,5,6,7,8,9 };
	auto iter = lst.begin();
	while (iter != lst.end()) {
		if (*iter % 2) {
			iter = lst.insert(iter, *iter);
			++iter;
			++iter;
		}
		else {
			iter = lst.erase(iter);
		}
	}
	for (auto i : lst) {
		cout << i << " ";
	}
	system("pause");
	return 0;
}

forward_list

#include<iostream>
#include<vector>
#include<forward_list>
using namespace std;

int main() {
	forward_list<int> lst = { 0,1,2,3,4,5,6,7,8,9 };
	auto iter = lst.begin();
	auto prev = lst.before_begin();
	while (iter != lst.end()) {
		if (*iter % 2) {
			iter = lst.insert_after(iter, *iter);
			prev = iter;
			++iter;
		}
		else {
			iter = lst.erase_after(prev);
		}
	}
	for (auto i : lst) {
		cout << i << " ";
	}
	system("pause");
	return 0;
}

练习9.34
行为是奇数复制,但由于每次插入奇数后返回的是仍是同一个奇数,于是会进入无限循环,应在每次插入奇数后跳过当前数。

#include<vector>
#include<iostream>

using namespace std;

int main() {
	vector<int> v = { 1,2,3,4,5 };
	auto iter = v.begin();
	while (iter != v.end()) {
		if (*iter % 2) {
			iter = v.insert(iter, *iter);
			++iter;
		}
		++iter;
	}
	for (auto i : v) {
		cout << i << " ";
	}
	system("pause");
	return 0;
}

练习9.37
list所占的空间不是连续的,array是固定size

练习9.38

#include <iostream>
#include <vector>
#include <string>

using namespace std;

int main()
{
    vector<string> v;

    for (string buffer; cin >> buffer; v.push_back(buffer))
        cout << v.size() << " " << v.capacity() << endl;

    return 0;
}

练习9.39
为svec预留了1024的空间,将输入添加到svec中,最后将svec的size增大当前的一半。

练习9.41

vector<char> v = { 'a','b','c' };
string s(v.begin(), v.end());

练习9.42

string s;
s.reserve(100);

练习9.43

#include<iostream>
#include<string>

using namespace std;

void func(string &s, string &oldVal, string &newVal) {
	auto iter = s.begin();
	while (iter + oldVal.size() != s.end()) {
		if (oldVal == string(iter, iter + oldVal.size())) {
			iter = s.erase(iter, iter + oldVal.size());
			iter = s.insert(iter, newVal.begin(), newVal.end());
			iter += newVal.size();
		}
		else {
			++iter;
		}
	}
}

int main() {
	string s("though,you don't love me");
	string oldVal("though");
	string newVal("tho");
	func(s, oldVal, newVal);
	cout << s;

	system("pause");
	return 0;
}

练习9.44

#include<iostream>
#include<string>

using namespace std;

void func(string &s, string &oldVal, string &newVal) {
	string::size_type i = 0;
	auto s_len = s.size(), old_len = oldVal.size();
	while (i + old_len <= s_len) {
		if (oldVal == s.substr(i, i + old_len)) {
			s.replace(i, i + old_len, newVal);
			i += newVal.size();
		}
		else {
			++i;
		}
	}
}
int main() {
	string s("though,you don't love me");
	string oldVal("though");
	string newVal("tho");
	func(s, oldVal, newVal);
	cout << s << endl;

	system("pause");
	return 0;
}

练习9.45

#include<iostream>
#include<string>

using namespace std;

void func(string &name, string &pre, string &post) {
	name.insert(0, pre);
	name.append(post);
}

int main() {
	string nm = "John", pre = "Mr.", post = " Jr.";
	func(nm, pre, post);
	cout << nm;
	system("pause");
	return 0;
}

练习9.46

void func(string &name, string &pre, string &post) {
	name.insert(0, pre);
	name.insert(name.size(), post);
}

练习9.47

#include<string>
#include<iostream>

using namespace std;

int main() {
	string str("ab2c3d7R4E6");
	string numbers{ "123456789" };
	string alphabet{ "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ" };
	string::size_type pos = 0;
	while ((pos = str.find_first_of(numbers, pos)) != string::npos) {
		cout << str[pos] << " ";
		++pos;
	}
	cout << endl;
	pos = 0;
	while ((pos = str.find_first_of(alphabet, pos)) != string::npos) {
		cout << str[pos] << " ";
		++pos;
	}
	cout << endl;

	pos = 0;
	while ((pos = str.find_first_not_of(alphabet, pos)) != string::npos) {
		cout << str[pos] << " ";
		++pos;
	}
	cout << endl;

	pos = 0;
	while ((pos = str.find_first_not_of(numbers, pos)) != string::npos) {
		cout << str[pos] << " ";
		++pos;
	}
	cout << endl;

	system("pause");
	return 0;
}

练习9.48
string::npos

练习9.49

#include<fstream>
#include<iostream>
#include<string>
#include<vector>

using namespace std;

int main() {
	string FileName;
	cout << "请输入要打开的单词文件:" << endl;
	cin >> FileName;
	ifstream inFile(FileName);
	if (!inFile) {
		cout << "打开失败!" << endl;
		return 0;
	}
	vector<string> ans;
	string up("bdfhklt"), down("gjpqy"), s;
	string::size_type pos = 0,poschar;
	while (inFile >> s) {
		if ((pos = s.find_first_of(up)) == string::npos) {
			if ((pos = s.find_first_of(down)) == string::npos) {
				ans.push_back(s);
			}
		}
	}
	for (auto i : ans) {
		cout << i << endl;
	}
	system("pause");
	return 0;
}

练习9.50

#include<string>
#include<iostream>
#include<vector>
using namespace std;

int main() {
	vector<string> vec = { "2","3","4","50" };
	int sum = 0;
	for (auto i : vec) {
		sum += stoi(i);
	}
	cout << sum << endl;

	system("pause");
	return 0;
}

练习9.51

#include<iostream>
#include<string>

using namespace std;

const string mm[12] = { "Jan","Feb","Mar","Apr","May","Jun","Jul","Aug","Sept","Oct","Nov","Dec" };

int findmonth(const string &mon) {
	int pos;
	for (int i = 0;i < 12;++i) {
		if ((pos = mon.find(mm[i])) != string::npos) {
			return i + 1;
		}
	}
}

class Date {
public:
	Date(const string &str) {
		string data_str = str;
		string::size_type index1 = 0;
		string::size_type index2 = 0;
		if (str.find(',') != string::npos) {
			index1 = str.find(' ');
			index2 = str.find(',',index1+1);
			string mon = str.substr(0, index1 - 1);
			month = findmonth(mon);
			day = stoi(str.substr(index1 + 1, index2));
			year = stoi(str.substr(index2 + 1));
		}
		else if (str.find('/') != string::npos) {
			index1 = str.find_first_of('/');
			index2 = str.find_first_of('/', index1 + 1);
			year = stoi(str.substr(index2 + 1));
			month = stoi(str.substr(index1 + 1, index2 - 1));
			day = stoi(str.substr(0, index1));
		}
		else {
			index1 = str.find_first_of(' ');
			index2 = str.find_first_of(' ', index1 + 1);
			string mon = str.substr(0, index1);
			month = findmonth(mon);
			day = stoi(str.substr(index1 + 1, index2 - 1));
			year = stoi(str.substr(index2 + 1));
		}
	}
	void getdate() {
		cout << "Year:" << year << " " << "Month:" << month << " " << "Day:" << day << endl;
	}
private:
	unsigned year, month, day;
};


int main() {
	string d1 = "January 1,1900", d2 = "1/1/1990", d3 = "Jan 1 1900";
	Date a(d1), b(d2), c(d3);
	a.getdate();
	b.getdate();
	c.getdate();

	system("pause");
	return 0;
}

练习9.52
题目意思表述的不太清楚,但大意是利用栈来求带括号表达式的值,下面只考虑加法的情况。
如果考虑加减乘除四则运算代码比较复杂,最好先转换成后缀表达式再求值。

#include<iostream>
#include<stack>
#include<string>
using namespace std;

bool isnum(char a) {
	if (a >= '0'&&a <= '9') {
		return true;
	}
	else return false;
}

int main() {
	string expr("(1+2)+(3+4)+5");
	stack<char> st;
	int sum = 0;
	int len = expr.size();
	for (int i = 0;i < len;i++) {
		if (expr[i] == '('|| isnum((expr[i]))) {
			st.push(expr[i]);
		}
		else if (expr[i] == '+') {
			continue;
		}
		else if (expr[i] == ')') {
			while (st.top() != '(') {
				sum += st.top() - '0';
				st.pop();
			}
			st.pop();
		}
	}
	while (!st.empty()) {
		sum += st.top() - '0';
		st.pop();
	}
	cout << sum << endl;

	system("pause");
	return 0;
}
posted @ 2019-03-15 17:37  Mered1th  阅读(1867)  评论(0编辑  收藏  举报